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Sedbober [7]
3 years ago
8

Mrs Belen wanted to bake 10 loaves of bread but realized she needed 1.75 more of flour. If she baked 7 loaves of bread she would

have 0.5 kg of flour left. How much flour was needed for each loaf of bread?
Mathematics
1 answer:
Pani-rosa [81]3 years ago
3 0
To answer this question, follow this step by step procedure:1. Add first the needed and the excess flour to determine to total flour, = (1.75 kg + 0.5 kg = 2.25)2. Then divide the answer by 3 since you need to have 3 more breads, 2.25 kg / 3 = 0.75 kg
So we can say that we need 0.75 kilogram of flour for each loaf of bread.
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Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56  

And rounded up we have that n=2663

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

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Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

t_{\alpha/2}=-2.58, t_{1-\alpha/2}=2.58

The margin of error for the proportion interval is given by this formula:  

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And on this case we have that ME =\pm 0.025 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

We can assume an estimated proportion of \hat p =0.5 since we don't have prior info provided. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56  

And rounded up we have that n=2663

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