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Sedbober [7]
3 years ago
8

Mrs Belen wanted to bake 10 loaves of bread but realized she needed 1.75 more of flour. If she baked 7 loaves of bread she would

have 0.5 kg of flour left. How much flour was needed for each loaf of bread?
Mathematics
1 answer:
Pani-rosa [81]3 years ago
3 0
To answer this question, follow this step by step procedure:1. Add first the needed and the excess flour to determine to total flour, = (1.75 kg + 0.5 kg = 2.25)2. Then divide the answer by 3 since you need to have 3 more breads, 2.25 kg / 3 = 0.75 kg
So we can say that we need 0.75 kilogram of flour for each loaf of bread.
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Can you help me please.​
Makovka662 [10]

Step-by-step explanation:

(3a - 15) - (9a + 2) \\  - 6a - 17

3 0
3 years ago
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What is 35.125 as a mixed number??
Sever21 [200]
The number can be separated into 35+0.125
0.125 can be rewritten as,
\frac{125}{1000}
So, the number can be rewritten;
35+\frac{125}{1000}
35\frac{125}{1000}
5 0
3 years ago
2/3x+15=17 please and thank you
frozen [14]

Answer:

x=3

Step-by-step explanation:

2/3x+15=17

first subtract 15 from both sides

2/3x=2

multiply by 3 to eliminate the fraction

2x=6

divide by 3

x=3

7 0
3 years ago
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What is the length of the diagonal of a square with a side that measures 11 centimeters
timofeeve [1]
A square has 4 equal sides
use pythagroeas theorem since a square has 4 right angles

a^2+b^2=c^2
a=b because the sides are equal (11)

11^2+11^2=c^2
242=c^2
square root both sides
11√2=c

the diagonal legnth is 11√2 centimiters
4 0
3 years ago
A radioactive substance decreases in the amount of grams by one-third each year. If the starting amount of the
katovenus [111]

Answer:

The sequence is geometric. The recursive formula is a_{n}=2/3a_{n-1}

Step-by-step explanation:

In order to solve this problem, you have to calculate the amount of the substance left after the end of each year to obtain a sequence and then you have to determine if the sequence is arithmetic or geometric.

The substance decreases by one-third each year, therefore:

After 1 year:

1452-\frac{1}{3}(1452)

Using 1452 as a common factor and solving the fraction:

1452(1-\frac{1}{3})=1452(\frac{2}{3})=968

You can notice that in general, after each year the amount of grams is the initial amount of the year multiplied by 2/3

After 2 years:

968(\frac{2}{3})=\frac{1936}{3}

After 3 years:

\frac{1936}{3}(\frac{2}{3})=\frac{3872}{9}

The sequence is:

1452,968,1936/3,3872/9....

In order to determine if the sequence is geometric, you have to calculate the ratio of two consecutive terms and see if the ratio is the same for all two consecutive terms. The ratio is obtained by dividing a term by the previous term.

The sequence is arithmetic if the difference of two consecutive terms is the same for all two consecutive terms.

-Calculating the ratio:

For the first and second terms:

968/1452=2/3

For the second and third terms:

1936/3 ÷ 968 = 2/3

In conclussion, the sequence is geometric because the ratio is common.

The recursive formula of a geometric sequence is given by:

a_{n}=ra_{n-1}

where an is the nth term, r is the common ratio and an-1 is the previous term.

In this case, r=2/3

7 0
3 years ago
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