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soldier1979 [14.2K]
3 years ago
9

Now use technology and use the cumulative probability​ 0.95, the mean muequals10.5​, and the standard deviation sigmaequals4.10

to determine the value for x0​, rounding to one decimal place.
Mathematics
1 answer:
makvit [3.9K]3 years ago
4 0

Answer:

18.5

Step-by-step explanation:

In the above question, we are given the following values

Cumulative probability ( confidence interval) = 0.95 = 95%

Mean = 10.5

Standard deviation = 4.10

We are asked to find the value of x.

To solve for x , we would be using the z score formula.

z score = (x-μ)/σ,

where x is the raw score,

μ is the population mean

σ is the population standard deviation

z score was not given in the question, but we have our cumulative probability as 95%(0.95).

Using the appropriate table,

the z score for 95% confidence is z = 1.96.

Therefore,

z score = (x-μ)/σ,

1.96 = x - 10.5/4.10

Cross multiply

1.96×4.10 = x - 10.5

x = (1.96 × 4.10) + 10.5

x = 8.036 + 10.5

x = 18.536

Approximately to 1 decimal place

x = 18.5

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What is the midpoint of np if N(10, -14) and P(-16, -4)?
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Answer:

<h3>Midpoint = (-3 ,-9)</h3>

Step-by-step explanation:

\\Midpoint =\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)\\\\\left(x_1,\:y_1\right)=\left(10,\:-14\right),\:\\\left(x_2,\:y_2\right)=\left(-16,\:-4\right)\\\\=\left(\frac{-16+10}{2},\:\frac{-4-14}{2}\right)\\\\=(\frac{-6}{2}, \frac{-18}{2}\\  \\Simplify\\\\=\left(-3,\:-9\right)

3 0
3 years ago
the company also discovered that it costs 30 to 2 widgets, 118 to produce 4 and 766 to produce 10 widgets. Find the total cost o
miv72 [106K]

We will first write cost function. As we are given three points here so we will use them to write quadratic function

y = ax^{2} +bx+c----------------------------------------(1)

So we will plug point (2,30) in it first ( for 2 widgets cost is 30)

So simply plug 30 in y place and 2 in x place in equation (1) as shown

30 = a(2)^{2} +b(2)+c

30 = 4a +2b +c ----------------------------------------------(2)

Similarly plug next point (4,118) now in equation (1)

118 = a(4)^{2} +b(4)+c

118 = 16a +4b +c ----------------------------------------------(3)

Similarly plug third point (10,766) now in equation (1)

766 = a(10)^{2} +b(10)+c

766 = 100a +10b +c ----------------------------------------------(4)

Now we have to solve system of linear equations (2),(3) and (4) for a,b,c

We can use method of elimination

Subtract equation (3) - equation (2)

118 = 16a +4b +c

-(30 = 4a +2b +c)

----------------------------------------------------

88 = 12a +2b -----------------------------------(5)

Similarly subtract equation (4)-equation (3)

766 =100a +10b +c

-( 118 = 16a +4b +c)

--------------------------------------

648 = 84a + 6b ------------------------(6)

Now to eliminate b in equations (5) and (6) multiply equation (5) by -3 and then add to equation (6)

-3×(88 = 12a +2b)

-264 = -36a - 6b

648 = 84a + 6b

---------------------------------

384 = 48a

Now solve for a

\frac{384}{48} = \frac{48a}{48}

8 = a

Plug 8 in a place in equation (5) or (6) and solve for b as shown

88 = 12(8) +2b

88 = 96 + 2b

88 -96 = 96 +2b -96

-8 = 2b

\frac{-8}{2} = \frac{2b}{2}

-4 = b

now plug 8 in a place, -4 in b place in either of equations (2),(3) or (4) and solve for c

30 = 4(8) +2(-4) +c

30 = 32 -8 + c

30 = 24 + c

30 - 24 = 24 + c - 24

6 = c

So plugging values of a as 8, b as -4 and c as 6 in equation (1) we get

y = 8x^{2} -4x+ 6

So thats the cost function. So now for 6 widgets, plug 6 in x place in this equation and find y value

y = 8(6)^{2} -4(6)+ 6

y = 8(36) - 24 +6

y = 288 -24 +6

y = 270

So $270 is the cost for producing 6 widgets and thats the final answer

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