Answer:
Proved
Step-by-step explanation:
To prove that every point in the open interval (0,1) is an interior point of S
This we can prove by contradiction method.
Let, if possible c be a point in the interval which is not an interior point.
Then c has a neighbourhood which contains atleast one point not in (0,1)
Let d be the point which is in neighbourhood of c but not in S(0,1)
Then the points between c and d would be either in (0,1) or not in (0,1)
If out of all points say d1,d2..... we find that dn is a point which is in (0,1) and dn+1 is not in (0,1) however large n is.
Then we find that dn is a boundary point of S
But since S is an open interval there is no boundary point hence we get a contradiction. Our assumption was wrong.
Every point of S=(0, 1) is an interior point of S.
The third quartile of this data set is B. 24.
It is A because the sum of E is 0+5=5 which is greater than 4 and X is 5+0=5 which is greater than four
Answer:
5050
Step-by-step explanation:
Answer:
4 x 13
Step-by-step explanation:
GCD of 28 and 24 is 4
28 = 4 x 7
24 = 4 x 6
u take the 4 out
4 (7 + 6)
4 x 13
