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Rainbow [258]
3 years ago
11

Why is it important to simplify rational expressions before multiplying or dividing? How do you determine that a rational expres

sion is in simplest form? Compare the process to addition and subtraction
Mathematics
1 answer:
lys-0071 [83]3 years ago
4 0

Answer:

"Simplifying rational expressions will make the further calculations easier since the variables to work with will usually be smaller.

To determine that a rational expression is in simplest form we need to make sure that the numerator and the denominator have no common variables."

Step-by-step explanation:

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Step-by-step explanation:

im a math genius

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Help me please I need it​
Masteriza [31]
Do 62 minus 3x-1. Whatever you get for that is the answer
4 0
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Mazyrski [523]

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the answer is 15/4

Step-by-step explanation:

all you have to do is take the independent variable and put the sign in between.

6 0
3 years ago
Solve the system of equations by using the inverse of the coefficient matrix of the equivalent matrix equation.
Alinara [238K]

The solution for the given system of equations x + 8y = -37, 4x + 8y = -52 is \left[\begin{array}{ccc}&5&\\\\&4&\end{array}\right]

Given,

System of equations as,

x + 8y = -37

4x + 8y = -52

We have to solve this by using the inverse of coefficient matrix of the equivalent matrix equation.

That is,

A=\left[\begin{array}{ccc}a&&b\\\\c&&d\end{array}\right]

A^{-1} =\frac{1}{ad -bc} \left[\begin{array}{ccc}d&&-b\\\\-c&&a\end{array}\right]

Now we can solve the equations.

Here we have,

x + 8y = -37

4x + 8y = -52

Now in matrix form,

\left[\begin{array}{ccc}1&&8\\\\4&&8\end{array}\right]  \left[\begin{array}{ccc}&x&\\\\&y&\end{array}\right] =\left[\begin{array}{ccc}&-37&\\\\&-52&\end{array}\right]

      A               X                  B

We know that,

A^{-1} =\frac{1}{ad -bc} \left[\begin{array}{ccc}d&&-b\\\\-c&&a\end{array}\right]

Therefore,

A^{-1} = \frac{1}{(1X8)-(4X8)} \left[\begin{array}{ccc}8&&-8\\\\-4&&1\end{array}\right]

       =\frac{1}{8-32} \left[\begin{array}{ccc}8&&-8\\\\-4&&1\end{array}\right]

       =\frac{1}{-24} \left[\begin{array}{ccc}8&&-8\\\\-4&&1\end{array}\right]

       =\left[\begin{array}{ccc}\frac{-8}{24} &&\frac{8}{24} \\\\\frac{4}{24} &&\frac{-1}{24} \end{array}\right]

Then,

\left[\begin{array}{ccc}&x&\\\\&y&\end{array}\right] ==\left[\begin{array}{ccc}\frac{-8}{24} &&\frac{8}{24} \\\\\frac{4}{24} &&\frac{-1}{24} \end{array}\right]  \left[\begin{array}{ccc}&\frac{37}{52} &\\\\\end{array}\right]

                =\frac{1}{24} \left[\begin{array}{ccc}-8&&8\\\\4&&-1\end{array}\right]\left[\begin{array}{ccc}&\frac{37}{52} &\\\\\end{array}\right]

                =\frac{1}{24} \left[\begin{array}{ccc}(-8X37)+(8X52)\\\\(4X37)+(-1X52)\end{array}\right]

               =\frac{1}{24} \left[\begin{array}{ccc}-296+416\\\\148-52\end{array}\right]

               =\frac{1}{24} \left[\begin{array}{ccc}120\\\\96\end{array}\right]

               =\left[\begin{array}{ccc}\frac{120}{24} \\\\\frac{96}{24} \end{array}\right]

              =\left[\begin{array}{ccc}5\\\\4\end{array}\right]

That is \left[\begin{array}{ccc}x\\\\y\end{array}\right] =\left[\begin{array}{ccc}5\\\\4\end{array}\right]

Learn more about matrix equations here: brainly.com/question/27799804

#SPJ4

The question is incomplete. Completed question is given below:

Solve The System Of Equations By Using The Inverse Of The Coefficient Matrix Of The Equivalent Matrix Equation.

x + 8y = -37

4x + 8y = -52

4 0
1 year ago
17 is added to a number, the result is 37 less than twice the number. Find the number
vesna_86 [32]

Answer:

x=6.67

Step-by-step explanation:

17+x=37-2x

17+x-x=37-2x-x

17=37-3x

17-37=37-37-3x

-20=-3x

-20/-3=-3x/3

6.666667=x

3 0
4 years ago
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