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Rainbow [258]
3 years ago
11

Why is it important to simplify rational expressions before multiplying or dividing? How do you determine that a rational expres

sion is in simplest form? Compare the process to addition and subtraction
Mathematics
1 answer:
lys-0071 [83]3 years ago
4 0

Answer:

"Simplifying rational expressions will make the further calculations easier since the variables to work with will usually be smaller.

To determine that a rational expression is in simplest form we need to make sure that the numerator and the denominator have no common variables."

Step-by-step explanation:

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Annie's great-grandparents lived in a log cabin with their 3 children. The log cabin had a floor area of 450 square feet. The ce
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Answer:

you would have to multiply 450•7

4 0
3 years ago
Use the angle relationship in the figure below to solve for x. Assume that lines a and b are parallel and the given angles are g
Daniel [21]

9514 1404 393

Answer:

  x = 5°

Step-by-step explanation:

The marked angles are "alternate exterior angles," hence congruent.

  2x +90° = x +95°

  x = 5° . . . . . . . . . . . . subtract (x+90°) from both sides

4 0
2 years ago
If a winning candidate received 8 votes for every 3 received by the loser, how many votes did each receive if the total number o
Mazyrski [523]

Answer:

Winner got 3920

Loser got 1470

Step-by-step explanation:

8 + 3 = 11

5390 / 11 = 490

490 * 8 = 3920

490 * 3 = 1470

7 0
2 years ago
Write the number in scientific notation. 322,000,000
Crazy boy [7]
It would be 3.22x10^8
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8 0
3 years ago
Read 2 more answers
Suppose X has an exponential distribution with mean equal to 23. Determine the following:
e-lub [12.9K]

Answer:

a) P(X > 10) = 0.6473

b) P(X > 20) = 0.4190

c) P(X < 30) = 0.7288

d) x = 68.87

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

Mean equal to 23.

This means that m = 23, \mu = \frac{1}{23} = 0.0435

(a) P(X >10)

P(X > 10) = e^{-0.0435*10} = 0.6473

So

P(X > 10) = 0.6473

(b) P(X >20)

P(X > 20) = e^{-0.0435*20} = 0.4190

So

P(X > 20) = 0.4190

(c) P(X <30)

P(X \leq 30) = 1 - e^{-0.0435*30} = 0.7288

So

P(X < 30) = 0.7288

(d) Find the value of x such that P(X > x) = 0.05

So

P(X > x) = e^{-\mu x}

0.05 = e^{-0.0435x}

\ln{e^{-0.0435x}} = \ln{0.05}

-0.0435x = \ln{0.05}

x = -\frac{\ln{0.05}}{0.0435}

x = 68.87

5 0
3 years ago
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