Hi there!
The two trapezoids are similar, so we can determine a common scale factor:
OL/UR = NM/TS
9/3 = 6/2
3 = 3
Trapezoid ONML is 3x larger than UTSR, so:
RS = 4, LM = y
3RS = LM
3 · 4 = y = 12.
Find x using the same method:
3UT = ON
3(2x+1) = 4x + 9
6x + 3 = 4x + 9
2x = 6
x = 3.
Answer:
10+2+0.3+0.05+0.007
Step-by-step explanation:
Part 1) we have that
volume smaller solid=512 cm³
volume larger solid=2197 cm³
we know that
volume larger solid=[scale factor]³*volume smaller solid
scale factor=∛[volume larger solid/volume smaller solid]
scale factor=∛[2197/512]-----> scale factor=1.625
Part 2)
the ratio of the surface areas is equal to [scale factor]²
1.625²-------> 2.64
Part 3)
surface area smaller solid=960 cm²
then
surface area larger solid=scale factor²*surface area smaller solid
surface area larger solid=[1.625]²*960-----> 2535 cm²
surface area larger solid is 2535 cm²
If f(x) has an inverse on [a, b], then integrating by parts (take u = f(x) and dv = dx), we can show
Let 
. Compute the inverse:
![f\left(f^{-1}(x)\right) = \sqrt{1 + f^{-1}(x)^3} = x \implies f^{-1}(x) = \sqrt[3]{x^2-1}](https://tex.z-dn.net/?f=f%5Cleft%28f%5E%7B-1%7D%28x%29%5Cright%29%20%3D%20%5Csqrt%7B1%20%2B%20f%5E%7B-1%7D%28x%29%5E3%7D%20%3D%20x%20%5Cimplies%20f%5E%7B-1%7D%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx%5E2-1%7D)
and we immediately notice that ![f^{-1}(x+1)=\sqrt[3]{x^2+2x}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%2B1%29%3D%5Csqrt%5B3%5D%7Bx%5E2%2B2x%7D)
.
So, we can write the given integral as
Splitting up terms and replacing 
in the first integral, we get
Answer:
x = 43
Step-by-step explanation:
180 - 65 = 115
115 = x + 72
<u>-72 -72 </u>
43 = x
x = 43
