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Nataliya [291]
3 years ago
6

How do you solve this using a picture and the work?

Mathematics
1 answer:
hoa [83]3 years ago
4 0
Okkk so u need to use the Pythagorean Theorum.
a x^{2} +b x^{2} =c x^{2}

a=x
b=1
c=5

so...
c x^{2} -b x^{2} =a x^{2}

5 x^{2} -1 x^{2} =a x^{2}

Solve that

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The circumference of a circle is 87 cm. What is the DIAMETER of the circle?
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Answer:

27.70

Step-by-step explanation:

you have to do 87 divided by the pi you only have to do 3.14 as the pi.

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Solve. -1/3b = 9<br> A.-3<br> B.3<br> C.-27<br> D.27
STALIN [3.7K]
Ok so lets plug in a first -1/3(-3) would equal 9 a is the accurate  answer
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2 years ago
There are 250 economy class seats on board. The airline sells some economy class seats at a discount price of $440 in advance an
Drupady [299]

Answer:

Check the explanation

Step-by-step explanation:

Cost of over reserving full cost tickets, Co = $440 ( empty seats as we cannot get even the discounted revenue)

Cost of under reserving Cu = 770-440 = $330 ( because you sell more discounted tickets)

Now critical ratio = Cu / (Cu+Co) = 330/770 = 0.42857

Now for above critical ratio ,z = -0.18 ( refer standard normal distribution table)

Optimal protection level = mean +z*standard deviation = 100-0.18*25 = 95.5 = 96

The possible costs include: all the above. You may need to provide compensation to passenger and make alternative travel arrangements. Also passenger won't be happy by over booking and their will be loss of good will.

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3 years ago
5. In the diagram shown below, BC is drawn tangent
Tatiana [17]

9514 1404 393

Answer:

 (2)  72°

Step-by-step explanation:

In this geometry, the angle at the tangent is half the measure of the intercepted arc.

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  ∠CBD = 72°

__

<em>Additional comment</em>

Consider a point X anywhere on long arc BD. The inscribed angle at X will have half the measure of short arc BD, so will be 144°/2 = 72°. This is true regardless of the position of X on long arc BD. Now, consider that X might be arbitrarily close to point B. The angle at X is still 72°.

As X approaches B, the chord XB approaches a tangent to the circle at B. Effectively, this tangent geometry is a limiting case of inscribed angle geometry.

6 0
3 years ago
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