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Nataliya [291]
3 years ago
6

How do you solve this using a picture and the work?

Mathematics
1 answer:
hoa [83]3 years ago
4 0
Okkk so u need to use the Pythagorean Theorum.
a x^{2} +b x^{2} =c x^{2}

a=x
b=1
c=5

so...
c x^{2} -b x^{2} =a x^{2}

5 x^{2} -1 x^{2} =a x^{2}

Solve that

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What is the answer to this question
Soloha48 [4]

(0,2),(-2,-1),(2,5)

-3x+2y=2

+3x    +3x

2y/2=3x+2/2

y=1 1/2x+2

Plug in numbers for x then solve for y

7 0
3 years ago
5. A deck should have a perimeter of 90 feet and a minimum area
Ket [755]

Answer:

The minimum value of the width is 15 ft and the maximum value of the width is 30 ft

Step-by-step explanation:

Let

x -----> the length of the deck

y ----> the width of the deck

we know that

The perimeter of the deck is equal to

P=2(x+y)

P=90\ ft

so

90=2(x+y)

45=(x+y)

x=45-y -----> equation A

The area is equal to

xy\geq 450 -----> inequality B  

(45-y)y\geq 450\\ \\-y^{2} +45y-450\geq 0

Solve the quadratic equation by graphing

The possible width of the deck are the values of y in the interval

[15,30]

All real numbers greater than or equal to 15 ft and less than or equal to 30 ft

see the attached figure

The minimum value of the width is 15 ft and the maximum value of the width is 30 ft

7 0
2 years ago
An autopilot attempts to maintain an airplane's altitude at a constant 18000 feet. because of random variations, the actual alti
valkas [14]

(a) A suitable probability app tells you the probability of being less than 17,900 or more than 18,100 is about 4.55%.

(b) We want to find σ² such that 2P((18100-18000)/σ) ≤ 0.01. We use a factor of 2 because we want to count deviations both above and below 100 feet from the mean altitude. A suitable probability app can tell you the z-score such that P(Z)≤0.005, so we need to compute σ² = (100/Z)² from that result. Doing so, we get σ² ≈ 1507.

4 0
3 years ago
Joseph ran LaTeX: 2\frac{3}{4}2 3 4 miles in LaTeX: \frac{2}{5}2 5 of an hour. How fast did Lin run in 1 hour? (try to leave you
Olegator [25]

Answer:

Nathaniel ran fastest

Step-by-step explanation:

For Joseph

Joseph ran 2 3/4 miles 2 /5 of an hour.

Speed = Distance/Time

Speed = 2 3/4 miles ÷ 2/5 hour

= 11/4 ÷ 2/5

= 11/4 × 5/2

= 55/8 miles/hour or 6.875 miles/hour

How fast did he run in 1 hour? (try to leave your answer in a fraction)

Hence, this is calculated as:

2/5 hour = 55/8 miles per hour

1 hour = x

Cross Multiply

x = 55/8 ÷ 2/5

x = 55/8 × 5/2

x = 275/16 miles per hour

x = 17 3/16 miles per hour

Nathaniel ran LaTeX: 8 2/3 miles in 4 /3 of an hour. How fast did Nathaniel run in 1 hour? (try to leave your answer in a fraction)

Speed = Distance/Time

Speed = 8 2/3 miles ÷ 4/3hour

= 26/3 ÷ 4/3

= 26/3 × 3/4

= 26/4 miles/hour

How fast did he run in 1 hour? (try to leave your answer in a fraction)

Hence, this is calculated as:

4/3 hour = 26/4miles per hour

1 hour = x

Cross Multiply

x = 26/4 ÷ 4/3

x = 26/4 × 3/4

x = 78/16 miles per hour

x = 4 14/16 miles per hour

= 4 7/8 miles per hour

Who ran the fastest, Nathaniel or Joseph?

Hence, from the calculation above, Nathaniel ran fastest

5 0
2 years ago
Evaluate g(x)=4 -3x when x=-3,0, and 5
4vir4ik [10]

Answer:

-11

Step-by-step explanation:

6 0
3 years ago
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