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3 years ago

How do you solve this using a picture and the work?

Mathematics

1 answer:

hoa [83]3 years ago

4 0

Okkk so u need to use the Pythagorean Theorum.
$a x^{2} +b x^{2} =c x^{2}$

a=x
b=1
c=5

so...
$c x^{2} -b x^{2} =a x^{2}$

$5 x^{2} -1 x^{2} =a x^{2}$

Solve that

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Select the property of equality used to arrive at the conclusion <br> if x-3=7 , then x=10

Fantom [35]

Answer:

The addition property of equality

Step-by-step explanation:

According to the addition property of equality, if we add the same number to each side of an equation, the equality is still true.

We are given the equation

x – 3 = 7, and we must solve for x.

We want to get x by itself, so we <em>add 3 to each side</em>.

x – 3 + 3 = 7 + 3

x = 10

We have just used the addition property of equality.

8 0

3 years ago

Suppose that S is the set of successful students in a classroom, and that F stands for the set of freshmen students in that clas

lora16 [44]

Answer:

b) 24

Step-by-step explanation:

We solve building the Venn's diagram of these sets.

We have that n(S) is the number of succesful students in a classroom.

n(F) is the number of freshmen student in that classroom.

We have that:

$n(S) = n(s) + n(S \cap F)$

In which n(s) are those who are succeful but not freshmen and $n(S \cap F)$ are those who are succesful and freshmen.

By the same logic, we also have that:

$n(F) = n(f) + n(S \cap F)$

The union is:

$n(S \cup F) = n(s) + n(f) + n(S \cap F)$

In which

$n(S \cup F) = 58$

$n(s) = n(S) - n(S \cap F) = 54 - n(S \cap F)$

$n(f) = n(F) - n(S \cap F) = 28 - n(S \cap F)$

$n(S \cup F) = n(s) + n(f) + n(S \cap F)$

$58 = 54 - n(S \cap F) + 28 - n(S \cap F) + n(S \cap F)$

$n(S \cap F) = 24$

So the correct answer is:

b) 24

3 0

4 years ago

At another school they sell a different brand of gift wrap which costs $2 per package and cards for $5 per package. Your friends

zhenek [66]

Hi there,

5x?=110 ?=22

how? 110/5=22

now 2x?=110

110/2=55 ?=55'

so we know now that people bought 22 packages with card and 55 w/th out cards!

so no we need to divide 695/both

695/5=139 packages with cards

695/2=347 packages without cards

SO

139 packages with card

347 packages without card

8 0

3 years ago

Is it possible to create two triangles with congruent side lengths but different angle measurements?

kotykmax [81]

Yes. If the side lengths are different, you can end up with different angle measurements (example: SSA~ property. You can have two sides that are the same but you can make two different triangles with those side lengths and that one angle.)

8 0

3 years ago

Use properties of addition to evaluate the expression. −35+7+(−15) Enter your answer in the box.

frutty [35]

Your answer will be -43

8 0

3 years ago