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2 years ago

Write the exponential equation in logarithmic form. e^(-3) ≈ .05

Mathematics

1 answer:

vodka [1.7K]2 years ago

7 0

Answer:

-3 = ln(0.05)

Step-by-step explanation:

Taking the natural log of both sides of the equation gives ...

-3·ln(e) = ln(0.05)

The natural log of e is 1, so the equation becomes ...

-3 = ln(0.05)

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Jane has 18 juice boxes, 24 bags of peanuts and 36 apples. She wants to make snack bags with same number of each thing in each b

pishuonlain [190]

Answer: 6 snack bags.

Step-by-step explanation:

For this exercise it is important to remember the Greatest Common Divisor (GCD). This is defined as the largest positive intener by which you can divided evenly "n" numbers.

In this case, you know that Jane has 18 juice boxes, 24 bags of peanuts and 36 apples. Therefore, the steps are the following:

1. You need to descompose 18, 24 and 36 into their prime factors, as below:

$18=2*3*3=2*3^2\\\\24=2*2*2*3=2^3*3\\\\36=2*2*3*3=2^2*3^2$

2. Now you must choose the common ones with the smallest exponent and multiply them.

Then, you get:

$GCD=3*2\\\\GCD=6$

Therefore, the greatest number of snack bags that Jane can make is: 6 snack bags.

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3 years ago

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Step-by-step explanation:

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2 years ago

The sum of two numbers is 20, and the difference is 40

Feliz [49]

$x+y=20\\\underline{x-y=40}\\2x=60\\x=30\\\\30+y=20\\y=-10$

<u>-10 and 30</u>

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3 years ago

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Mrs. johnson's and mr. wei's classes are participating in the Meridian School arts and crafts exhibit. Their spaces will be next

Nat2105 [25]

Answer:

See explanation

Step-by-step explanation:

Ms. Johnson space has 48 carpet squares.

Mr. Wei space has 36 carpet squares.

Factorize these two numbers:

$48=2\cdot 2\cdot 2\cdot 2\cdot 3\\ \\36=2\cdot 2\cdot 3\cdot 3$

All common factors are 1, 2, 3, 4, 6, 12

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1. If Ms. Johnson space width and Mr. Wei space width is 1 carpet, then Ms. Johnson space length is 48 carpets and Mr. Wei space length is 36 carpets.

2. If Ms. Johnson space width and Mr. Wei space width is 2 carpets, then Ms. Johnson space length is 24 carpets and Mr. Wei space length is 18 carpets.

3. If Ms. Johnson space width and Mr. Wei space width is 3 carpets, then Ms. Johnson space length is 16 carpets and Mr. Wei space length is 12 carpets.

4. If Ms. Johnson space width and Mr. Wei space width is 4 carpets, then Ms. Johnson space length is 12 carpets and Mr. Wei space length is 9 carpets.

5. If Ms. Johnson space width and Mr. Wei space width is 6 carpets, then Ms. Johnson space length is 8 carpets and Mr. Wei space length is 6 carpets.

6. If Ms. Johnson space width and Mr. Wei space width is 12 carpets, then Ms. Johnson space length is 4 carpets and Mr. Wei space length is 3 carpets.

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