Equation of a line with slip of 5 passing through points (-4,-6)

1 answer:

5 0

$\bf (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-6})~\hspace{10em} slope = m\implies 5 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-6)=5[x-(-4)] \\\\\\ y+6=5(x+4)\implies y+6=5x+4\implies y=5x-2$

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I'll do the first two problems to get you started

Problem 1

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Like with problem 1, I multiplied top and bottom of the first fraction by the value 5 which is the denominator of the second fraction. Likewise, I did the same for the second fraction using the first denominator. The steps are essentially the same, but the numbers are different.

Problem 3 will be handled the same way. I'll let you try it out.

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