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3 years ago

Simplify. -9 -5 -7 х Y Z 2 6 3 X Y Z

Mathematics

1 answer:

krok68 [10]3 years ago

7 0

Answer:

$= {x}^{ - 11} {y}^{ - 11} {z}^{ - 10}$

Step-by-step explanation:

$= \frac{ {x}^{ - 9} {y}^{ - 5} {z}^{ - 7} }{ {x}^{2} {y}^{6} {z}^{3} } \\ = {x}^{ - 9 - 2} {y}^{ - 5 - 6} {z}^{ - 7 - 3} \\ = {x}^{ - 11} {y}^{ - 11} {z}^{ - 10}$

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The car is moving with a speed v0 = 48 mi/hr up the 4-percent grade, and the driver applies the brakes at point A, causing all w

lutik1710 [3]

Answer:

s = 0.2203 miles

Step-by-step explanation:

Given:

- The initial speed vo = 48 mi/hr

- The mass of the car m

- The coefficient of kinetic friction uk = 0.61

- The slope of the road 4-percent grade

Find:

Determine the stopping distance sAB. Repeat your calculations for the case when the car is moving downhill from B to A.

Solution:

- Apply the energy principle with work done against friction:

K.E_1 + P.E_1 = Wf + P_E_2 + K.E_2

- The final velocity of car is zero, K.E_2 = 0

The initial potential energy is set as zero, P.E_1 = 0

K.E_1 = Wf + P_E_2

0.5*m*vo^2 = Ff*s + m*g*h

Where, Ff is the frictional force:

Ff = uk*N

Where, N is the normal contact force between car and road. By equilibrium equation we have:

m*g*cos(θ) - N = 0

N = m*g*cos(θ)

Hence,

Ff = uk*m*g*cos(θ)

- The vertical distance travelled h is:

h = s*sin(θ)

- The energy equation is:

0.5*m*vo^2 = uk*m*g*cos(θ)*s + m*g*s*sin(θ)

0.5*vo^2 = uk*g*cos(θ)*s + g*s*sin(θ)

s*(uk*g*cos(θ) + g*sin(θ) ) = 0.5*vo^2

s = [0.5*vo^2 / (uk*g*cos(θ) + g*sin(θ) ) ]

- The slope = 4 / 100,

s = [0.5*48^2 / (0.61*8052.97*cos(2.29) + 8052.97*sin(2.29) ) ]

s = 0.2203 miles

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3 years ago

Compare and contrast expressions equations and inequalities

babymother [125]

Equations can have one solution, but inequalities have infinite solutions.

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3 years ago

1Ox+6-8x=9x +12-8x-2

Goshia [24]

Answer:

X=4

Step-by-step explanation:

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3 years ago

Find the solution set to each inequality. Express the solution in set notation.

daser333 [38]

The solution to the inequality 6m + 2 > -27 is m > -4.33

The solution to the inequality 8(p-6)>4(p-4) is p > 8

The given inequality is:

6m + 2 > - 27

Subtract 2 to both sides of the inequality

6m + 2 - 2 > -27 - 2

6m > -29

Divide both sides by 6

$\frac{6m}{6}> \frac{-29}{6} \\m > \frac{-29}{6}\\m > -4.83$

For the inequality 8(p-6)>4(p-4)

Expand the inequality using the distributive rule

8p - 48 > 4p - 16

Collect like terms

8p - 4p > -16 + 48

4p > 32

Divide both sides of the inequality 4

$\frac{4p}{4} > \frac{32}{4}\\p > 8$

The solution to the inequality 6m + 2 > -27 is m > -4.33

The solution to the inequality 8(p-6)>4(p-4) is p > 8

Learn more here: brainly.com/question/15816805

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