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3 years ago

9

Look at the following math problems. 10 + 2 = 12 12 − 2 = 10 What are these operations called?

2 answers:

Nadusha1986 [10]3 years ago

7 0

I think they are called "inverse operations."

Sonbull [250]3 years ago

7 0

They are called inverse operations:

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Plz write this on paper help me and send it❤️

vovangra [49]

Answer:

1. $27^{\frac{2}{3} } =9$

2. $\sqrt{36^{3} } =216$

3. $(-243)^{\frac{3}{5} } =-27$

4. $40^{\frac{2}{3}}=4\sqrt[3]{25} =4325$

5. Step 4: $(\frac{343}{27}) ^{-1} =\frac{27}{343}$

6. $D. -72cd^{7}$

Step-by-step explanation:

Use the following properties:

$a^{\frac{x}{y} } =\sqrt[x]{a^{y} }$

$\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}$

$a^{-n} =\frac{1}{a^{n} }$

$(xy)^{z} =x^{z} y^{z} \\\\$

$(x^{y}) ^{z} =x^{yz}$

$x^{y} x^{z} =x^{y+z}$

So:

1. $27^{\frac{2}{3} } =\sqrt[3]{27^{2}} =\sqrt[3]{729} }=9$

2. $\sqrt{36^{3} } =\sqrt{36*36*36} =\sqrt{36} \sqrt{36} \sqrt{36} =6*6*6=216$

3. $(-243)^{\frac{3}{5} } =\sqrt[5]{-243^{3} } =\sqrt[5]{-14348907} =-27$

4. $40^{\frac{2}{3}}=\sqrt[3]{40^{2} } =\sqrt[3]{2^{6} 5^{2} } =\sqrt[3]{2^{6} } \sqrt[3]{5^{2} } =2^{\frac{6}{3} } 5^{\frac{2}{3} } =4 *5^{\frac{2}{3} } =4\sqrt[3]{5^{2} } =4\sqrt[3]{25}=4325$

5. $(\frac{343}{27}) ^{-1} =\frac{1}{\frac{343}{27} } =\frac{27}{343}$

6.

$(-8c^{9} d^{-3} )^{\frac{1}{3} } *(6c^{-1}d^{4})^{2} =\sqrt[3]{-8} c^{3} d^{-1} 36c^{-2} d^{8} \\\\-2c^{3} d^{-1} 36c^{-2} d^{8}=-72cd^{7}$

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3 years ago

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2 years ago

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20 POINTS * A circle has a radius of 6. An arc in this circle has a central angle of 48°

storchak [24]

Answer:

$\frac{8\pi}{5}$

Step-by-step explanation:

Since this is a degree we going to use the arc length formula

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where x is the central angle measure and r is the radius.

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$2\pi \times (6)( \frac{48}{360} )$

Multiply 2 pi by 6

$12\pi \times ( \frac{48}{360} )$

$12\pi \times \frac{4}{30}$

$\frac{12\pi}{1} \times \frac{4}{30} = \frac{48\pi}{30}$

$\frac{8\pi}{5}$

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3 years ago