SOLUTION
Given B is the midpoint of AC ABBC 1 and C is the midpoint of BD BCCD2 ie on adding 1 and 2 ART We get ABBCBCCD hence ABCD hence proved
Answer:
![{27}^{ \frac{1}{3} } = \sqrt[3]{27} = \sqrt[3]{3 \times 3 \times 3} = \boxed{ 3}✓](https://tex.z-dn.net/?f=%20%7B27%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7B27%7D%20%20%3D%20%20%5Csqrt%5B3%5D%7B3%20%5Ctimes%203%20%5Ctimes%203%7D%20%20%3D%20%5Cboxed%7B%203%7D%E2%9C%93)
<h3>3. <em><u>3</u></em> is the right answer.</h3>
Answer:
<u><em>14 pounds of strawberries and 42 pounds of peaches are sold</em></u>
Step-by-step explanation:
Suppose the pounds of strawberries sold are x and pounds of peaches sold are y. then
$182= x(1) + y(4)--------A
or 182= x(1) +3x(4)------- B
182=x+12x
182/13=x
x=14
Answer:
A+B=B+A
B+0=B
E-C=E+(-C)
Step-by-step explanation:
I think the best figure for a cereal box would be a cylinder. There are no corners on a cylinder where it is hard to fit round pieces of cereal into. The formula for the surface area of the cylinder is 2*pi*r*h+2*pi*r^2. The formula for the volume of the cylinder is pi*r^2*h. (Then I would add some more info supporting why you think a cylinder would make a good box.)
