They are examples of non sworn personnel
Answer:
26.64%
Explanation:
Common stocks outstanding (C) = 80 million
Preffered stock outstanding (P) = 60 million
Number of bonds (B) = 50,000
Cost of common stock (Cc) = $20 per share
Cost of Preffered stock (Cp) = $10 per share
Cost of bond (Cb) = 105% of par
Weight of preferred stock :
(P * Cp) / [(P*Cp) + (C*Cc) + (B * Cb * par value)]
(60mill * $10) / [(60mill * $10) + (80mill * $20) + (50000 * 1.05 * 1000)]
600mill / (600 mill + 1600mill + 52.5mill)
600,000,000 / 2252500000
= 0.2663706
= 26.64%
Answer:
Required rate of return= 16%
Stock price= $13.50
Explanation:
A share of BAC common stock just made a dividend payment of $1
Market return is 12%
Beta is 1.5
Risk-free rate is 4%
Growth rate is 8%
The required rate of return for the stock can be calculated as follows
Required rate of return= Risk-free rate+beta×(market rate-risk-free rate)
= 4%+1.5(12%-4%)
= 4%+1.5×8%
= 4%+12
= 16%
The stock price can be calculated as follows
Stock price= dividend for the year/(rate of return-growth rate)
= (1×1.08)/(16/100-8/100)
= 1.08/0.16-0.08
= 1.08/0.08
= $13.50
Hence the required rate of return and the stock price is 16% and $13.50 respectively.
Answer:
Bette's Breakfast should increase the price or change the cost´s structure.
Explanation:
Bette's Breakfast should increase the price to get any profits because the total of the cost of serving that breakfast is higher than the price.
Profit= price* sales -((Variable cost * sales) +Fixed cost)
Other option is changing the structure of cost per meal.
Answer:
C) Generalizable
Explanation:
Christian is testing the generalizability of the cognitive ability test used in the advertising industry on a printing and publishing company. This is used to know if the same test (cognitive ability) administered on different industry will yield to the same result.
Christian wants to know if the cognitive test is a generalizable method.
Generalizability: This is a research process carried out to determine if the test used on a particular sample can be used on other samples. It provides information on the effectiveness of the same test on different samples. It is used to know if the the same test administered to different samples will produce the same result. Findings can be deducted from the test results.
