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serg [7]
3 years ago
8

If the points (4,2) (6,3) and (8,4) are on the graph of f, give three points on the graph of f^-1

Mathematics
1 answer:
Stels [109]3 years ago
8 0

let's recall that an inverse function has the same pair of coordinates as the original function, but backwards, or namely the inverse's range is the original's domain.

\bf \stackrel{f(x)}{\begin{array}{|cc|ll} \cline{1-2} 4&2\\ 6&3\\ 8&4\\ \cline{1-2} \end{array}}\qquad \qquad \stackrel{f^{-1}(x)}{\begin{array}{|cc|ll} \cline{1-2} 2&4\\ 3&6\\ 4&8\\ \cline{1-2} \end{array}}

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2(3x+4y) = 2(24)
6x+8y = 48
Add both the equations
6x + 8y = 48
+ x - 8y = -20
—————————
7x = 28
x = 28/7
x = 4

Plug in this value in the second equation

(4) - 8y = -20
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y = -24/-8
y = 3

Therefore:
x = 4
y = 3
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