Answer:
0.321 is the probability that their mean printing speed of the sample is greater than 17.99 ppm.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 17.39 ppm
Standard Deviation, σ = 4.25 ppm
Sample size = 11
We are given that the distribution of printing speed is a bell shaped distribution that is a normal distribution.
Formula:
P(printing speed of the sample is greater than 17.99 ppm.)
P(x > 17.99)

Calculating the value from the standard normal table we have,

Thus, 0.321 is the probability that their mean printing speed of the sample is greater than 17.99 ppm.
Answer:
x=25/64
Step-by-step explanation:
by simple substitution
Answer:
-3x^2+6x-157
Step-by-step explanation:
Answer:
0.013
Step-by-step explanation:
Use binomial probability:
P = nCr pʳ (1−p)ⁿ⁻ʳ
where n is the number of trials,
r is the number of successes,
and p is the probability of success.
Given n = 6, p = 0.69, and r = 0 or 1:
P = ₆C₀ (0.69)⁰ (1−0.69)⁶⁻⁰ + ₆C₁ (0.69)¹ (1−0.69)⁶⁻¹
P = (1) (1) (0.31)⁶ + (6) (0.69) (0.31)⁵
P = 0.013