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3 years ago

Solve the equation. A.-22 1/2 B.10 C.25 D.22 1/2

Mathematics

1 answer:

sdas [7]3 years ago

4 0

It’s D because if you enter 22.5 it gives you 9 and 9=9

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Sam’s fish tank has a base area of 187 in2 and a height of 16

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997 1/3 in 3

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3 years ago

In ΔIJK, the measure of ∠K=90°, the measure of ∠J=76°, and JK = 3.6 feet. Find the length of IJ to the nearest tenth of a foot.

Nataly_w [17]

This is my answer
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3 0

3 years ago

Type your answer into the box. X 30° Calculate the size of angle x. angle x =

andrezito [222]

Answer:

60°

Step-by-step explanation:

90°+30°=120°

180°_120°=60°

4 0

3 years ago

Read 2 more answers

part 2. Find the value of the trig function indicated, use for that Pythagorean theorem to find the third side if you need it.

andreev551 [17]

Answer: $\bold{5)\ \cos \theta=\dfrac{\sqrt{11}}{6}\qquad 6)\ \tan \theta =\dfrac{8}{17}\qquad 7)\ \cos \theta = \dfrac{4}{3}\qquad 8)\ \cos \theta = \dfrac{\sqrt{10}}{10}}$

Step-by-Step Explanation:

Pythagorean Theorem is: a² + b² = c² , where "c" is the hypotenuse

$5)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{3\sqrt{11}}{18}\quad \rightarrow \large\boxed{\dfrac{\sqrt{11}}{6}}$

Note: (15)² + (3√11)² = hypotenuse² → hypotenuse = 18

$6)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{8}{17}\quad =\large\boxed{\dfrac{8}{17}}$

Note: 8² + 15² = hypotenuse² → hypotenuse = 17

$7)\ \tan \theta=\dfrac{\text{side opposite to}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{20}{15}\quad \rightarrow \large\boxed{\dfrac{4}{3}}$

Note: hypotenuse not needed for tan

$8)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{2}{2\sqrt{10}}\quad =\large\boxed{\dfrac{\sqrt{10}}{10}}$

Note: 2² + 6² = hypotenuse² → hypotenuse = 2√10

8 0

3 years ago

What is the area of the shaded region below? 7 m 30 m 7 m 21 m

Rama09 [41]

Answer:

322.28

Step-by-step explanation:

Area of the rectangle

L = 30

W = 21

Area = 30 * 21

Area = 630

Area of the circles

Radius = 7 m

Area = pi r^2

Area = 3.14 * 7^2

Area = 153.86 m^2

Area of both circles = 307.72

Area of the Shaded Region

Area of shaded region = area of the rectangle - area of 2 circles.

Area of Shaded Region = 630 - 307.72

Area of Shaded Region = 322.28

5 0

3 years ago