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Nastasia [14]
3 years ago
6

Help please! Thanks in advance

Mathematics
1 answer:
svetoff [14.1K]3 years ago
7 0
So line b is (0,0) and (4, -3/2)

slope = m = y2-y1/ x2-x1

= -3/2 - 0 / (4-0 )= -3/8

now using point slope y-y1=m(x-x1)

m=-3/8 and point is (0,0) to make it easier
y-0 = -3/8 (x-0)
y=-3/8x

so we have the first line done, now another line is parallel to line b which means they have the same slope

line 2 has slope = m = -3/8
and point (0,-7)

using point slope again y-y1=m(x-x1)

y- (-7) = (-3/8) (x-0)

y=(-3/8)x -7

hope that helps and is right
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Alicia has 7 paintings she wants to hang side by side on her wall.
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The question is an illustration of permutation and combinations.

  • The number of ways she can choose 4 out of the 7 paintings is 35
  • The number of ways she can arrange 4 out of the 7 paintings is 840

The given parameters are:

\mathbf{n = 7}

\mathbf{r = 4}

<u>(a) Choose 4 of 7 paintings</u>

Choosing 4 of 7 paintings implies combination.

So, we have:

\mathbf{^nC_r = \frac{n!}{(n - r)!r!}}

Substitute values for n and r

\mathbf{^7C_4 = \frac{7!}{(7 - 4)!4!}}

\mathbf{^7C_4 = \frac{7!}{3!4!}}

Expand

\mathbf{^7C_4 = \frac{7 \times 6 \times 5 \times 4!}{3 \times 2 \times 1 \times 4 !}}

\mathbf{^7C_4 = 35}

Hence, the number of ways she can choose 4 out of the 7 paintings is 35

<u>(b) Arrange 4 of 7 paintings</u>

Arranging 4 of 7 paintings implies permutation.

So, we have:

\mathbf{^nP_r = \frac{n!}{(n - r)!}}

Substitute values for n and r

\mathbf{^7P_4 = \frac{7!}{(7 - 4)!}}

\mathbf{^7P_4 = \frac{7!}{3!}}

Expand

\mathbf{^7P_4 = \frac{7 \times 6 \times 5 \times 4 \times 3!}{3!}}

\mathbf{^7P_4 = 840}

Hence, the number of ways she can arrange 4 out of the 7 paintings is 840

Read more about permutation and combinations at:

brainly.com/question/15301090

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