Can you explain what u mean.
Answer:
B. 3 g/mL
Step-by-step explanation:
The first thing is to know the density formula:
Density is given as follows:
d = m / V
let m: mass and V: volume.
We have that the mass of the metal is 1800 grams and the volume of 600 milliliters.
Therefore, replacing:
d = 1800/600 = 3 g / mL
That is, the density is 3 grams per milliliter.
Answer:
![x = 15](https://tex.z-dn.net/?f=x%20%3D%20%2015)
![y = 25](https://tex.z-dn.net/?f=y%20%3D%20%2025)
Step-by-step explanation:
Given
See attachment for MNPQ and RSTU
Required
Find x and y
To solve this question, we make use of equivalent ratios of corresponding side lengths.
The ratio of corresponding sides are:
![MN : RS](https://tex.z-dn.net/?f=MN%20%3A%20RS)
![NP : ST](https://tex.z-dn.net/?f=NP%20%3A%20ST)
![PQ : TU](https://tex.z-dn.net/?f=PQ%20%3A%20TU)
![MQ : RU](https://tex.z-dn.net/?f=MQ%20%3A%20RU)
From the attachment, we have:
![MN : RS \to 18 : 30](https://tex.z-dn.net/?f=MN%20%3A%20RS%20%5Cto%2018%20%3A%2030)
![NP : ST \to x : 25](https://tex.z-dn.net/?f=NP%20%3A%20ST%20%5Cto%20x%20%3A%2025)
![PQ : TU \to 15 : y](https://tex.z-dn.net/?f=PQ%20%3A%20TU%20%5Cto%2015%20%3A%20y)
To solve for x, we equate
and ![NP : ST](https://tex.z-dn.net/?f=NP%20%3A%20ST)
![18 : 30 = x : 25](https://tex.z-dn.net/?f=18%20%3A%2030%20%3D%20x%20%3A%2025)
Express as fraction
![\frac{18 }{ 30 }= \frac{x }{ 25}](https://tex.z-dn.net/?f=%5Cfrac%7B18%20%7D%7B%2030%20%7D%3D%20%5Cfrac%7Bx%20%7D%7B%2025%7D)
Make x the subject
![x = 25 * \frac{18 }{ 30 }](https://tex.z-dn.net/?f=x%20%3D%20%2025%20%2A%20%5Cfrac%7B18%20%7D%7B%2030%20%7D)
![x = \frac{25 * 18 }{ 30 }](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B25%20%2A%2018%20%7D%7B%2030%20%7D)
![x = \frac{450}{ 30 }](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B450%7D%7B%2030%20%7D)
![x = 15](https://tex.z-dn.net/?f=x%20%3D%20%2015)
To solve for y, we equate
and ![PQ : TU](https://tex.z-dn.net/?f=PQ%20%3A%20TU)
![18 : 30 = 15 : y](https://tex.z-dn.net/?f=18%20%3A%2030%20%3D%2015%20%3A%20y)
Express as fraction
![\frac{18 }{ 30 }= \frac{15 }{ y}](https://tex.z-dn.net/?f=%5Cfrac%7B18%20%7D%7B%2030%20%7D%3D%20%5Cfrac%7B15%20%7D%7B%20y%7D)
Make y the subject
![y = 15 * \frac{30 }{ 18 }](https://tex.z-dn.net/?f=y%20%3D%2015%20%2A%20%5Cfrac%7B30%20%7D%7B%2018%20%7D)
![y = \frac{15 *30}{ 18 }](https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B15%20%2A30%7D%7B%2018%20%7D)
![y = \frac{450}{ 18 }](https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B450%7D%7B%2018%20%7D)
![y = 25](https://tex.z-dn.net/?f=y%20%3D%20%2025)
Answer:
480
Step-by-step explanation:
Let h represent the number of high-quality downloads. Then the total download size is ...
4.1h +2.7(1130-h) = 3723
1.4h = 672 . . . . . . . . . . . . . . subtract 2.7·1130 = 3051
h = 480 . . . . . . . divide by 1.4
There were 480 downloads of the high-quality version.
We know that
They are 4 Lateral sides on <span>the regular quadrilateral pyramid</span>,
so
if one of them is 48 cm²,
we multiply it by 4,
48 cm²*4------> 192 cm²
the answer is
The Lateral area of the pyramid is 192 cm²