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2 years ago

Each 6 students reported the number of movies they saw in the past year 18,14,18,14,19,9

Mathematics

1 answer:

Brilliant_brown [7]2 years ago

8 0

Answer:

Average: Add all and divide by 6

that gives us 92/6 = 15.333... or 15

Median: order it:

9, 14, 14, 18, 18, 19

median is 16

2 averages

Median: 16

Average: 15.33.. or 15

Outlier: 9

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Karen is 6 years older than her sister Michelle, and Michelle is 2 years younger than their brother David. If the sum of their a

ale4655 [162]

$K\ \rightarrow\ the\ Karen's\ age\\M\ \rightarrow\ the\ Michelles\ age \\D\ \rightarrow\ the\ David's\ age\\\\K=M+6\\M=D-2\ \ \ \Rightarrow\ \ \ D=M+2\\K+M+D=62\\\\(M+6)+M+(M+2)=62\\3M+8=62\\3M=54\ /:3\\M=18\ \ \ \Rightarrow\ \ \ K=18+6=24\ \ \ and\ \ \ D=18+2=20\\\\Ans.\ Michelle\ is\ 18,\ David\ is\ 20,\ Karen\ is\ 24.$

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2 years ago

The U.S. Mint produces quarters that weigh about 5.67 grams each. After the

lesantik [10]

The U.S. Mint makes commercial circulation coins including commemorative collection's coins including investor bullion coins.
In the case of circular coins, the quantities were measured in terms of figures for "production" numismatic categories in order "sales" and bullion "mintage" statistics.

$\to \bold{|x-5.67|=0.02}\\\\$

heaviest $\bold{=5.69\ g\\\\}$

lighest $\bold{=5.65\ g\\\\}$

Evaluating the each expression:

$\to \bold{q = -8}\\\\ \to \bold{r = -6}\\\\ \to \bold{t=3}$

Learn more:

brainly.com/question/20845315

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3 years ago

Complete the factorization of 4x2 – 9.

Nastasia [14]

Your Answer would be:

4x2<span> – 9 = (2x - 3)(2x + 3)
</span>
Hope this helps!

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3 years ago

Read 2 more answers

Aside from playing scrabble, what ither indoor recreational activities would you intiate in your family/community despite tha pa

olga nikolaevna [1]

Sungka. Playing sungka is fun

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2 years ago

Determine which of the sets of vectors is linearly independent. A: The set where p1(t) = 1, p2(t) = t2, p3(t) = 3 + 3t B: The se

defon

Answer:

The set of vectors A and C are linearly independent.

Step-by-step explanation:

A set of vector is linearly independent if and only if the linear combination of these vector can only be equalised to zero only if all coefficients are zeroes. Let is evaluate each set algraically:

$p_{1}(t) = 1$ , $p_{2}(t)= t^{2}$ and $p_{3}(t) = 3 + 3\cdot t$ :

$\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0$

$\alpha_{1}\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (3 +3\cdot t) = 0$

$(\alpha_{1}+3\cdot \alpha_{3})\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot t = 0$

The following system of linear equations is obtained:

$\alpha_{1} + 3\cdot \alpha_{3} = 0$

$\alpha_{2} = 0$

$\alpha_{3} = 0$

Whose solution is $\alpha_{1} = \alpha_{2} = \alpha_{3} = 0$ , which means that the set of vectors is linearly independent.

$p_{1}(t) = t$ , $p_{2}(t) = t^{2}$ and $p_{3}(t) = 2\cdot t + 3\cdot t^{2}$

$\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0$

$\alpha_{1}\cdot t + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (2\cdot t + 3\cdot t^{2})=0$

$(\alpha_{1}+2\cdot \alpha_{3})\cdot t + (\alpha_{2}+3\cdot \alpha_{3})\cdot t^{2} = 0$

The following system of linear equations is obtained:

$\alpha_{1}+2\cdot \alpha_{3} = 0$

$\alpha_{2}+3\cdot \alpha_{3} = 0$

Since the number of variables is greater than the number of equations, let suppose that $\alpha_{3} = k$ , where $k\in\mathbb{R}$ . Then, the following relationships are consequently found: