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taurus [48]
3 years ago
10

Each 6 students reported the number of movies they saw in the past year 18,14,18,14,19,9

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
8 0

Answer:

Average: Add all and divide by 6

that gives us 92/6 = 15.333... or 15

Median: order it:

9, 14, 14, 18, 18, 19

median is 16

2 averages

Median: 16

Average: 15.33.. or 15

Outlier: 9

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If 2 variables have a negative correlation, then the slope of the line of best fit will be ______.
Lana71 [14]
Negative, because Correlation and slope have the same direction (Sxy will be negative)
5 0
3 years ago
Prove the trigonometric identity
Annette [7]

Answer:

Proved See below

Step-by-step explanation:

Man this one is a world of its own :D Just a quick question are you a fellow Add Math student in O levels i remember this question from back in the day :D Anyhow Lets get started

For this question we need to know the following identities:

1+tan^{2}x=sec^2x\\\\1+cot^2x=cosec^2x\\\\sin^2x+cos^2x=1

Lets solve the bottom most part first:

1-\frac{1}{1-sec^2x} \\\\

Take LCM

1-\frac{1}{1-sec^2x} \\\\\frac{1-sec^2x-1}{1-sec^2x} \\\\\frac{-sec^2x}{1-sec^2x} \\\\\frac{-(1+tan^2x)}{-tan^2x}

now break the LCM

\frac{-1}{-tan^2x}+\frac{-tan^2x}{-tan^2x}\\\\\frac{1}{tan^2x}+1\\\\cot^2x+1

because 1/tan = cot x

and furthermore,

cot^2x+1\\cosec^2x

now we solve the above part and replace the bottom most part that we solved with cosec^2x

\frac{1}{1-\frac{1}{cosec^2x} } \\\\\frac{1}{1-sin^2x} \\\\\frac{1}{cos^2x}\\\\sec^2x

Hence proved! :D

4 0
3 years ago
How do you simplify fractions
MariettaO [177]
Divide top and bottom by any number that's fits into both of them keep doing that until it's not possible Hope that helped Have a good day! :-)
5 0
3 years ago
Read 2 more answers
I need answers for 1 and 2
Snowcat [4.5K]

1. Slope 3/4, through (4,-1)

y = 3/4 x + b

-1 = 3/4(4) + b

-1 = 3 + b

-1 - 3 = b

-4 = b

y = 3/4 x - 4

2. Slope = - 1/2, through (3,0)

y = -1/2 x + b

0 = -1/2(3) + b

0 = -1.5 + b

0 + 1.5 = b

1.5 = b

y = -1/2 x + 1.5

8 0
3 years ago
I need help please and thank you
Thepotemich [5.8K]
By solving 1 & 2
no solution.
4 0
3 years ago
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