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tangare [24]
3 years ago
7

What is the least value of the data represented by the box plot? Enter your answer in the box. A number line ranging from 5 to 4

5 with a box encompassing the numbers 20, 25, and 30.
Mathematics
2 answers:
brilliants [131]3 years ago
4 0
To find the least number in the box plot, You will look at where the line on the left-hand side stops in the left.

Based on the information you gave, it seems the line would stop at the 5.

If it does, the least value of the data, called the lower extreme, would be 5.
alexandr402 [8]3 years ago
4 0

Answer:

5

Step-by-step explanation:

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3 years ago
HIJ Inc. Purchases a truck for $32,000 on January 1st, 2019. The vehicle is estimated to have a useful life of 15 years, at whic
Artyom0805 [142]

Answer:

#See solution and attached for details

Step-by-step explanation:

Straight line method assumes a gradual depreciation in value of an asset's useful life.

-It's calculated by dividing the difference between an asset's cost and its expected salvage value by the number of years it is expected to be used.

Dep/yr=(A-Salvage)/n\ \ \ \ \ \ n=15, A=32000\\=(32000-2000)/15\\=2000

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5 0
3 years ago
Write the equation of the parabola in vertex form
Tpy6a [65]

Answer:

y = -(x - 2)^2.

Step-by-step explanation:

Vertex form is a(x - b)^2 + c   where  a is a constant and (b, c) is the vertex.

Here b = 2 and c = 0

So we have:

y = a( x - 2)^2 + 0

When x = 4 y = -4 so:

-4 = a( 4 - 2)^2

a = -4/2^2 = -1

So the required equation is

y = -(x - 2)^2.

8 0
3 years ago
Complete the point-slope equation of the line through (3,-8) (6,-4)
Ganezh [65]

Answer:

y + 4 = 4/3(x - 6).

Step-by-step explanation:

The point-slope formula is shown below. We just need to find the slope.

(-4 - (-8)) / (6 - 3) = (-4 + 8) / 3 = 4 / 3

m = 4/3, y1 = -4, and x1 = 6.

y - (-4) = 4/3(x - 6)

y + 4 = 4/3(x - 6).

Hope this helps!

3 0
4 years ago
The center of mass is defined as a point on the straight line between two objects with masses m1 and m2 such that . What are the
STatiana [176]
Let the point be P, and the masses be located at P1 and P2.

The centre of mass is such that the moments of masses m1 and m2 exert an equal moment at the point P,
and the distance P1P2=d
namely,

m1(mPP1)=m2(mPP2)
The distance of the centre of mass from m1 is therefore
d1=d*m2/(m1+m2)
Similarly, the distance of the centre of mass from m2 is
d2=d*m1/(m1+m2)
5 0
3 years ago
Read 2 more answers
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