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Bezzdna [24]
4 years ago
6

Jeff drinks 2/3 of a glass of juice. Write a fraction equivalent to 2/3

Mathematics
1 answer:
Rufina [12.5K]4 years ago
7 0
A fraction that means the same as 2/3 is 4/6.

To find this, you can simply multiple both the numerator and denominator (top and bottom) by any number as long as it's the same number for both top and bottom.
In this case, we used 2 as the number, and multipled it to the top and bottom of 2/3, to get 4/6.

I hope this helps!
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If f(x) = 4x – 6, what is f(6)?
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Salaries for various positions can vary significantly depending on whether the company is in the public or private sector. The U
DIA [1.3K]

Answer:

a) 0.004

b) 0.9609                                                

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 76503

Standard Deviation, σ = 8850

We are given that the distribution of annual salaries is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(salary greater than 100,000)

P(x > 100000)

P( x > 100000) = P( z > \displaystyle\frac{100000 - 76503}{8850}) = P(z > 2.655)

= 1 - P(z \leq 2.655)

Calculation the value from standard normal z table, we have,  

P(x > 100000) = 1 - 0.996 = 0.004  = 0.4\%

b) P(sample mean annual salary falls between 70,000 and 80,000 dollars)

Sample size, n = 20

Standard error due to sampling =

\dfrac{\sigma}{\sqrt{n}} = \dfrac{8850}{\sqrt{20}} = 1978.92

P(70000 \leq x \leq 80000) = P(\displaystyle\frac{70000 - 76503}{1978.92} \leq z \leq \displaystyle\frac{80000-76503}{1978.92})\\\\ = P(-3.286 \leq z \leq 1.767)\\\\= P(z \leq 1.767) - P(z < -3.286)\\=0.9614 - 0.0005= 0.9609 = 96.09\%

P(70000 \leq x \leq 80000) = 96.09\%

7 0
4 years ago
Suppose that we wanted to estimate the true average number of eggs a queen bee lays with 95 percent confidence. The margin of er
svetoff [14.1K]

Answer:

At least 1537 samples needed to estimate the true average number of eggs a queen bee lays with 95 percent confidence

Step-by-step explanation:

Minimum sample size required can be found using the formula

N≥(\frac{z*s}{ME} )^2 where

  • N is the sample size
  • z is the corresponding z-score of 95% confidence level (1.96)
  • s is the standard deviation (10)
  • ME is the margin of error (0.5)

then N≥(\frac{1.96*10}{0.5} )^2 =1536.64

Then, at least 1537 samples needed to estimate the true average number of eggs a queen bee lays with 95 percent confidence

6 0
4 years ago
Lesson 1.2 practice a
sergejj [24]

we need a picture or a typed out question to help, sorry!

3 0
3 years ago
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