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3 years ago

Washing 24 cars in four hours what is the Relationship as a rate

Mathematics

1 answer:

jekas [21]3 years ago

8 0

Answer:

6 cars per hour

Step-by-step explanation:

The rate can be expressed several ways. One of them is "cars per hour". To find that rate, divide cars by hours:

(24 cars)/(4 hours) = 6 cars/hour

If 6 cars were washed in 60 minutes, another way to express the rate is ...

(60 minutes)/(6 cars) = 10 minutes/car

When you ask "what is the rate?", you need to be specific as to the rate you're interested in. Different expressions of the rate are useful for different purposes.

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What is 85% of 540 sales

Sonja [21]

.85 x 540 = 459 85% is written as .85 of means to multiply so you're going to multiply .85 X 540 which equals 459

7 0

3 years ago

The circumference of a circle is 3 pie inches. What is the area of the circle

sweet [91]

Answer:

A = 28.26

Step-by-step explanation:

Hello!! The area is:

A = 3.14 ( 3 )²

A = 3.14 ( 9 )

A = 28.26

7 0

3 years ago

The square root of four more than three times a number is seven. Find the number.

faltersainse [42]

Answer:

Yup the answer is 15!

Step-by-step explanation:

(3x + 4)^(1/2) = 7

3x + 4 = 49

3x = 45

x = 15

5 0

3 years ago

Read 2 more answers

expeople1 [14]

Answer:

i dont understand you question

Explanation:

mind explaining it to me better so i can help

6 0

4 years ago

Read 2 more answers

a rectangular dog kennel is to be constructed alongside a house with 60m of fencing. If the house serves as one side of the kenn

Basile [38]

Answer:

$450\text{ m}^2$ .

Step-by-step explanation:

Let x represent side of kennel opposite to house and y represent other sides.

We have been given that a rectangular dog kennel is to be constructed alongside a house with 60 m of fencing.

Since fencing will cover 3 sides of kennel, so perimeter of kennel would be:

$x+y+y=60$

$x+2y=60$

Let us solve for x.

$x+2y-2y=60-2y$

$x=60-2y$

The area of the kennel would be product of its sides that is:

$\text{Area}=x\cdot y$

Now, we will substitute $x=60-2y$ in area equation as:

$A(y)=(60-2y)\cdot y$

$A(y)=60y-2y^2$

Let us find the derivative as shown below:

$A'(y)=60-4y$

Now, we will set derivative equal to 0 and solve for y.

$60-4y=0$

$60=4y$

$\frac{60}{4}=\frac{4y}{4}$

$y=15$

Upon substituting $y=15$ in area function, we will greatest possible area.

$A(y)=60y-2y^2$

$A(15)=60(15)-2(15)^2$

$A(15)=900-2(225)$

$A(15)=900-450$

$A(y)=450$

Therefore, the greatest possible area that can be enclosed by 60 m of fencing is 450 square meters.

5 0

3 years ago