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4 years ago

Washing 24 cars in four hours what is the Relationship as a rate

Mathematics

1 answer:

jekas [21]4 years ago

8 0

Answer:

6 cars per hour

Step-by-step explanation:

The rate can be expressed several ways. One of them is "cars per hour". To find that rate, divide cars by hours:

(24 cars)/(4 hours) = 6 cars/hour

If 6 cars were washed in 60 minutes, another way to express the rate is ...

(60 minutes)/(6 cars) = 10 minutes/car

When you ask "what is the rate?", you need to be specific as to the rate you're interested in. Different expressions of the rate are useful for different purposes.

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What is the value of x? (Bottom of the Picture included)

aleksandr82 [10.1K]

Answer:

Step-by-step explanation:

3 0

3 years ago

A particle starts at the point P=(−5,−1,3) when t=0 and moves along a straight line toward Q=(−6,−6,8) at a speed of 9 cm/sec. L

navik [9.2K]

Answer:

Step-by-step explanation:

Given

Particle moves from $P\ (-5,-1,3)\ to\ Q\ (-6,-6,8)$

speed of particle is $v=9\ cm/s$

Unit vector in the direction of vector $\vec{PQ}$ is given by

$\hat{n}=\frac{\vec{Q}-\vec{P}}{|\vec{Q}-\vec{P}|}$

$\hat{n}=\frac{-}{\sqrt{(-1)^2+(-5)^2+(5)^2}}$

$\hat{n}=\frac{}{\sqrt{1+25+25}}$

Now Position of Particle at any time is given by

$\vec{r(t)}=velocity\cdot time\cdot direction$

$\vec{r(t)}=9\cdot t\cdot \frac{}{\sqrt{1+25+25}}$

Parametric vector equation is given by

$x=\frac{-9t}{\sqrt{51}}$

$y=\frac{-45t}{\sqrt{51}}$

$z=\frac{45t}{\sqrt{51}}$

6 0

4 years ago

Jamar is finding (-2)(-3)(-4). Find his mistake and correct it. Explain your answer.

vichka [17]

The correct answer would be (-24). When multiplying with negative integers, negative times negative is positive, however, the final answer, in this case, is negative because you are then multiplying a positive and a negative:
(-2)(-3)=6
6(-4)=(-24)
I'm guessing Jamar's mistake was he multiplied all of them thinking his answer would be a positive integer: 24.

6 0

3 years ago

Guys I need help pleaSe !!!

dangina [55]

Answer:

The equations that represent an exponential decay are;

A; [y = (0.1)ˣ]

B; [y = 2·(0.3)ˣ]

Step-by-step explanation:

An exponential decay is given by the following formula;

y = a·bˣ

Where;