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Ne4ueva [31]
2 years ago
5

The diameter of a circle is 14 miles. What is the circle's area? Use 3.14 for ​.

Mathematics
1 answer:
aksik [14]2 years ago
7 0

Answer:

153.86cm^2

Step-by-step explanation:

area of a circle= πr^2

where r = radius= 14/2= 7miles

area= 3.14×(7×7)

area= 3.14×49= 153.86cm^2

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PLEASE HELP!!! FINDING PROBABILITY MATH!!! expert help would be nice
ozzi

The probability that a person wins the game is 32.1%

<h3>How to illustrate the probability?</h3>

Based on the information given, the following can be depicted. It should be noted that there are 6 sides as well as 4 cards.

Therefore, the numbers on the dice i.e from 1 - 6 will be represented 4 times each. This gives a total of (4 × 6) = 24. There are also 4 cards. The total in sample space will now be:

= 24 + 4 = 28

The frequency table will be such that 28 or more have a relative frequency of 9. Therefore, the probability that a person wins the game will be:

= 9/28 = 32.1%

When you win 25% of the time, this illustrates that the number of products picked will be:

= 25% × 28

= 7 products.

The probability of participants achieving a winning score of 36 or higher in four consecutive attempts will be:

= 1/6⁴ = 1/1296

Learn more about probability on:

brainly.com/question/24756209

#SPJ1

6 0
1 year ago
how many pounds of coffee worth $10 a pound should be added to 20 pounds of coffee worth $4 a pound to get a mixture worth $5 a
Solnce55 [7]

Answer:

4

Step-by-step explanation:

1. if the mass of coffee worth $10 is 'x', then its worth is 10x, and the worth of the mixture is 5(x+20);

2. using the previous item it is possible to write the next equation:

5(x+20)=4*20+10*x; ⇒ x=4.

3. the required mass is 4 pounds.

5 0
3 years ago
Help please
natta225 [31]
Using V = ⅓[base area×height]
V= ⅓[ (5.5÷4)² × 2.6]
v= ⅓[ 4.92]
v = 1.6m³
8 0
3 years ago
Find the value of x
Dvinal [7]
Answer
67.5

45° would be the other angle of 2x°

180° - 45° = 135°

135/45 = 67.5°
6 0
3 years ago
Can you help me with my work
Pachacha [2.7K]
h(0)=3

The diver begins 3 meters above the water

----------------------------

\begin{gathered} h(1)=8 \\ 8>6.75>3 \end{gathered}

The diver reaches a maximum height of 8ft

The

3 0
1 year ago
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