Given :
A graph with a straight line on it.
To Find :
The equation of the line.
Solution :
From the given graph we can see that the line passes through point ( 0,6 ) and ( 4,10 ) .
Also, equation of line passes through two points
and
is :

Putting all given values, we get :

Therefore, the equation of line is y - x = 6 .
Answer:
<h3>B. 4units</h3>
Step-by-step explanation:
Find the diagram attached. The diagram is a similar triangle.
From the diagram, XZ/XY = CA/AB
Given XZ = 2x-2+2x-2 = 4x-4
XY =5x-7
CA = 2x-2
AB= x+1
On substituting this parameters into the formula to get x first
4x-4/5x-7 = 2x-2/x+1
cross multiply
(4x-4)(x+1) = 5x-7(2x-2)
open the parenthesis
4x²+4x-4x-4 = 10x²-10x-14x+14
4x²-4 = 10x²-24x+14
10x²-4x²-24x+14+4 = 0
6x²-24x+18 = 0
x²-4x+3 = 0
x²-3x-x+3 = 0
x(x-3)-1(x-3) =0
(x-3)(x-1) = 0
x = 3 and 1
Next is to get length AX.
Given AX = 2x-2
Substitute x = 3 into the expression
AX = 2(3)-2
AX = 6-2
AX = 4 units
Hence the measure of length AX is 4 units
A B C D E represent the subjects
A+A1
A+B2
A+C3
A+D4
A+E5
B+B6
B+C7
B+D8
B+E9
C+C10
C+D11
C+E12
D+D13
D+E14
E+E15
15 combos
Using the unit circle, the coordinates of 3π/4 is :
![(-\frac{\sqrt[]{2}}{2},\frac{\sqrt[]{2}}{2})](https://tex.z-dn.net/?f=%28-%5Cfrac%7B%5Csqrt%5B%5D%7B2%7D%7D%7B2%7D%2C%5Cfrac%7B%5Csqrt%5B%5D%7B2%7D%7D%7B2%7D%29)
Note that tangent function can be solved using the formula y/x
where x and y are the coordinates of the angle.
This will be :
![\frac{\sqrt[]{2}}{2}\div(-\frac{\sqrt[]{2}}{2})=-1](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B%5D%7B2%7D%7D%7B2%7D%5Cdiv%28-%5Cfrac%7B%5Csqrt%5B%5D%7B2%7D%7D%7B2%7D%29%3D-1)
The answer is -1
Divide it by 25 witch is the height then find the square root