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3 years ago

7

Blake has b baseball cards. His aunt gave him more cards, increasing his total number of cards by 25%. Which expression represen

ts Blake’s total number of cards now

2 answers:

Vera_Pavlovna [14]3 years ago

6 0

.25b+ b is the answer to ur question

Keith_Richards [23]3 years ago

3 0

B + ( b x 0.25) = X
this should work

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Two circular cylinders are similar. The ratio of the areas of their bases is 9:4. Find the ratio of the volumes of the similar s

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Answer:

27 : 8

Step-by-step explanation:

Given 2 similar figures with ratio of sides a : b, then

ratio of areas = a² : b² and

ratio of volumes = a³ : b³

Here the ratio of areas = 9 : 4, thus

ratio of sides = $\sqrt{9}$ : $\sqrt{4}$ = 3 : 2

ratio of volumes = 3³ : 2³ = 27 : 8

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3 years ago

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x=15

Step-by-step explanation:

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3 years ago

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Jim read 24 pages in 40 minutes on Tuesday and 18 pages in 24 minutes on Wednesday. Are the ratios of pages read to minutes on T

IRISSAK [1]

Answer: Not proportional

Step-by-step explanation:

Ratio of pages read by Jim on Tuesday to minutes = $\frac{24}{40}=\frac{3}{5}=3:5$

Ratio of pages read by Jim on Wednesday to minutes = $\frac{18}{24}=\frac{3}{4}=3:4$

But $\frac{3}{5}\neq \frac{3}{4}$

Therefore, the ratios of pages read to minutes on Tuesday and Wednesday are not proportional.

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3 years ago

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PLEASE HELP ITS DUE IN A FEW MINUTES

sladkih [1.3K]

A. Fish man, goron, smith, other
B.98 people voted for goron, explanation 28 times 10 would equal 280 which is the number of people who voted, so every 10% percent would be 28 people
C, no 40 people is not correct multiple 40 times 10 and it’s 400 which is over the amount of people who voted

5 0

2 years ago

The federal government would like to test the hypothesis that the average age of men filing for Social Security is higher than t

mixas84 [53]

Answer:

The 90% confidence interval is $-0.3433< \mu_1 - \mu_2 < 2.1433$

Step-by-step explanation:

From the question we are told that

The sample mean for men is $\= x_1 = 64.5 \ years$

The sample mean for women is $\= x_2 = 63.6 \ years$

The sample size for men is $n_1 = 35$

The sample size for women is $n_2 = 39$

The standard deviation for men is $s_1 = 3.0$

The standard deviation for women is $s_2 = 3.5$

From the question we are told the confidence level is 90% , hence the level of significance is

$\alpha = (100 - 90 ) \%$

=> $\alpha = 0.10$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the standard error is mathematically represented as

$SE = \sqrt{\frac{s_1^2 }{n_1} + \frac{s_2^2}{n_2} }$

=> $SE = \sqrt{\frac{3^2 }{35} + \frac{3.5^2}{39} }$

=> $SE = 0.7558$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * SE$

=> $E = 1.645 * 0.7558$

=> $E = 1.2433$

Generally 90% confidence interval is mathematically represented as

$(\= x_1 - \= x_2) -E < \mu_1 - \mu_2 < (\= x_1 - \= x_2) -E$

=> $(64.5 - 63.6) -1.2433< \mu_1 - \mu_2$

=> $-0.3433< \mu_1 - \mu_2 < 2.1433$

7 0

2 years ago