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4 years ago

Please answer this question now in two minutes

Mathematics

2 answers:

dolphi86 [110]4 years ago

5 0

Step-by-step explanation:

using 30°

we use cos

cos 30 =10√3/U
U = 10√3/Cos30 =20cm

using 60

we use Sin

Sin 60=10√3/U
U = 10√3/Sin60 = 20

lord [1]4 years ago

4 0

Answer:

Step-by-step explanation:

use the cos or sin function to solve

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Find an equation of the line that is parallel to the graph of 2x+3y=5 and contains the point (3, −1).

uranmaximum [27]

Answer:

A) Equation of line is 3X - 2Y = 11

B) Equation of line is Y = X + 1

C) Equation of line is Y - 7 = 0

Equation of line , point (3 , -1) and slop $\frac{3}{2}$ is 3X - 2Y = 11

Step-by-step explanation:

Given equation of line as 2x + 3y = 5

slove of this line (m1) = - $\frac{2}{3}$

Now another line passes through point (3 , -1) having slop (m2)

Both lines are parallel to each other, i.e (m1) × (m2) = - 1

So slop of second line (m2 ) = $\frac{-1}{m1}$

(m2) = $\frac{-1}{(\frac{-2}{3} } )$

(m2) = $\frac{3}{2}$

Now eq of line with point (3 , -1) and slop (m2)

Y- y1 = (m2)( X - x1)

Or, Y +1 = $\frac{3}{2}$ (X - 3)

i.e 2Y + 2= 3X - 9

∴ Equation of line is 3X - 2Y = 11 Answer

B) Given points as ( 5,6) and (3 , 4)

Slop (m) = $\frac{y2 - y1}{x2 - x1}$ = $\frac{4 - 6}{3 - 5}$ = 1

So the equation of line is

Y- y1 = (m)( X - x1)

Y - 6 = (1) (X - 5)

i.e Equation of line is Y = X + 1 Answer

C) Given points as ( 0, 7) , (0 , -8)

Slop (m) with co-ordianate = $\frac{y2 - y1}{x2 - x1}$

Or, = $\frac{-8 - 7}{0 - 0}$

Hence equation of line is Y - 7 = 0 Answer

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3 years ago

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andrey2020 [161]

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