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3 years ago

Need help with number 9 please, thanks.

Mathematics

1 answer:

timurjin [86]3 years ago

3 0

Its point P because the lines between 1 and 2 are 1/4 2/4 and 3/4 and its looking for 1 1/4 so the correct is the line after number 1 on the x axis and the y axis is 2 which you can see p is located it

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Jake ate 55% of a cake. What fraction of the cake did he eat?

7nadin3 [17]

Answer:

11/20

Step-by-step explanation:

To be able to find the fraction of the cake that Jake ate if you know that he ate 55% of it, you have to turn the 55% into a fraction. To do this, first you have to divide the percent by 100:

55/100

Then, you have to simplify the fraction. In this case, you can do it by dividing by 5:

11/20

According to this, the fraction of the cake that Jake ate is 11/20.

8 0

3 years ago

I never understand math

zloy xaker [14]

0.17
Explain: looked it up and also use Symbolab it’s a math calculator

8 0

2 years ago

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3. The curve C with equation y=f(x) is such that, dy/dx = 3x^2 + 4x +k

Andreas93 [3]

a. Given that y = f(x) and f(0) = -2, by the fundamental theorem of calculus we have

$\displaystyle \frac{dy}{dx} = 3x^2 + 4x + k \implies y = f(0) + \int_0^x (3t^2+4t+k) \, dt$

Evaluate the integral to solve for y :

$\displaystyle y = -2 + \int_0^x (3t^2+4t+k) \, dt$

$\displaystyle y = -2 + (t^3+2t^2+kt)\bigg|_0^x$

$\displaystyle y = x^3+2x^2+kx - 2$

Use the other known value, f(2) = 18, to solve for k :

$18 = 2^3 + 2\times2^2+2k - 2 \implies \boxed{k = 2}$

Then the curve C has equation

$\boxed{y = x^3 + 2x^2 + 2x - 2}$

b. Any tangent to the curve C at a point (a, f(a)) has slope equal to the derivative of y at that point:

$\dfrac{dy}{dx}\bigg|_{x=a} = 3a^2 + 4a + 2$

The slope of the given tangent line $y=x-2$ is 1. Solve for a :

$3a^2 + 4a + 2 = 1 \implies 3a^2 + 4a + 1 = (3a+1)(a+1)=0 \implies a = -\dfrac13 \text{ or }a = -1$

so we know there exists a tangent to C with slope 1. When x = -1/3, we have y = f(-1/3) = -67/27; when x = -1, we have y = f(-1) = -3. This means the tangent line must meet C at either (-1/3, -67/27) or (-1, -3).

Decide which of these points is correct:

$x - 2 = x^3 + 2x^2 + 2x - 2 \implies x^3 + 2x^2 + x = x(x+1)^2=0 \implies x=0 \text{ or } x = -1$

So, the point of contact between the tangent line and C is (-1, -3).

7 0

2 years ago

Estimate the product of 68 and 21

Nataly_w [17]

The product of 68 and 21 would be 1,428.

5 0

3 years ago

Read 2 more answers

A reflection across the x-axis keeps the x-coordinate the same but flips the y-coordinate. What do you think a reflection across

Studentka2010 [4]

Answer: A reflection across the x-axis keeps the x-coordinates the same but flips the signs of the y-coordinates. So, it should be the opposite for a reflection across the y-axis. The y-coordinates remain the same, but the signs of the x-coordinates change.

Step-by-step explanation

I copy and pasted the answer

8 0

3 years ago