Answer:
AC = 23 so it be D
Step-by-step explanation:
plug AC = DF ---> 21x-19 = 3x+17
sub. 3x by both sides --> 18x-19 = 17
add 19 to both sides --> 18x = 36
divide both sides by 18, x = 2
plug x back into 21x-19 to find AC
21(2) - 19
42 - 19 = 23
The answer is F. what i did was reflect it over the axis then move each point five units right
Answer:
8.2 units
Step-by-step explanation:
Given that the only information for our triangle are 2 sides and 1 angle, we must use the Law of Cosines to find side BC
<u />
<u>Recall the Law of Cosines</u>
<u />
<u>Identify angles and sides</u>
<u />
<u>Solve for side "a"</u>
<u />
Therefore, the length of line segment BC is about 8.2 units
Answer:he started with 20
Step-by-step explanation:
The side length is 2.24 inches.
The area of a square is given by s²; we have
s² = 5
To find the value of s, we take the square root of each side:
√s² = √5
s = √5 = 2.236 ≈ 2.24