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3 years ago

14

a napkin has an area of 5 square inch . what is the side length of the napkin to the nearest hundredth of an inch?

1 answer:

mart [117]3 years ago

4 0

The side length is 2.24 inches.

The area of a square is given by s²; we have
s² = 5

To find the value of s, we take the square root of each side:
√s² = √5
s = √5 = 2.236 ≈ 2.24

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Name the place of the highlighted digit

enot [183]

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3 years ago

Order these numbers for lest to greatest 1/2 ,1.1 ,5/3 ,2, 0 ,0.4, -2 ,5/8

Nat2105 [25]

The least number should always start off with negatives if there are any. In this case there is so we can start with -2 as our least amount. Next are the small fractions. If you're allowed a calculator, I would use that to find what the decimals will look like for each fraction:

$\frac{1}{2} =0.5\\ \\ \frac{5}{3} =1.6666666666666666666666666666667\\ \\ \frac{5}{8} =0.625$

After -2 the next least number is 0 and the next one is the fraction or decimal closest to the number 0 which is 0.4

The next number would be from the fractions we solved earlier. 0.5 and 0.625 would follow 0.4 and then 1.1 and 1.6667(solved for from fraction).

Here is the list:

$-2,0,0.4,\frac{1}{2} ,\frac{5}{8} ,1.1,\frac{5}{3}$

Hope this helps!

6 0

3 years ago

Answer to this ?????????

marin [14]

9= h/9

Mutiply both sides by 9

9*9= h/9*9

Cross out 9 and 9 , divide by 9 and then becomes h

9*9= 81

Answer: h= 81

3 0

3 years ago

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An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed

masya89 [10]

Answer:

$P(X\leq 1) = 0.331$

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

$P(X = x) = \frac{y^xe^{-y}}{x!}$

Where y represents λ (average)

y = 2.3

<em>Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment</em>

<em />

Using probability notations;

$P(X\leq 1) = P(X=0) + P(X =1)$

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

$P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}$

$P(X = 0) = \frac{1 * e^{-2.3}}{1}$

$P(X = 0) = e^{-2.3}$

$P(X = 0) = 0.10025884372$

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

$P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}$

$P(X = 1) = \frac{2.3 * e^{-2.3}}{1}$

$P(X = 1) =2.3 * e^{-2.3}$

$P(X = 1) = 2.3 * 0.10025884372$

$P(X = 1) = 0.23059534055$

$P(X\leq 1) = P(X=0) + P(X =1)$

$P(X\leq 1) = 0.10025884372 + 0.23059534055$

$P(X\leq 1) = 0.33085418427$

$P(X\leq 1) = 0.331$

Hence, the required probability is 0.331

6 0

3 years ago

Please anyone help me

sineoko [7]

Hey There!!!!

The Answer Is > 240 x 3 = 720 so 720 is your answer!!

Please Mark Me Brainliest :) :) Annierosehodge (: (:

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3 years ago

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