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GarryVolchara [31]
2 years ago
13

Derrick has $4 to play video games at the mall each game cost a quarter to play. What’s the total number of games he can play

Mathematics
2 answers:
Alborosie2 years ago
5 0
Derrick can play 16 games in total.
Shtirlitz [24]2 years ago
5 0
He could play 16 games with his $4.00!
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Insert parentheses to make each statement true<br><br> -8+3-2+7=-16
quester [9]
 this is the answer and where the parentheses -8+(3-2)+7=-16
8 0
3 years ago
Can someone please explain?
AlladinOne [14]
<h2>Hello!</h2>

The answer is:

The correct option is the first option:  

y=-4x+64

<h2>Why?</h2>

To write the equation of the line in slope-interception  form we need to extract all the information that we need from the graphic.

We must remember that the slope-interception form of the lines is:

y=mx+b

Where,

y, is the function

m, is the slope of the line

x, is the variable

b, is the y-axis intercept

We can find the slope using the following formula:

m=\frac{ChangeInY}{ChangeInX}

Which is for this case:

m=\frac{64}{16}=4

As we can see from the graphic, the line is decresing, so the sign of the slope "m" will be negative, so:

m=-4

We can find the value of "b" seeing where the line intercepts the y-axis.

As we can see it intercept the y-axis at:  y=64

Then, now that we already know the value of "m" and "b", we can write the equation of the line:

y=mx+b=-4x+64\\y=-4x+64

So, the correct option is the first option:

y=-4x+64

Have a nice day!

4 0
3 years ago
What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove
wolverine [178]

Answer:

The solutions are:

b=0,\:b=4

Step-by-step explanation:

Considering the expression

  • \frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

Solving the expression

\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c

5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2

5b^3-10=6b^3-4b^2-10

\mathrm{Switch\:sides}

6b^3-4b^2-10=5b^3-10

6b^3-4b^2-10+10=5b^3-10+10

6b^3-4b^2=5b^3

\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}

6b^3-4b^2-5b^3=5b^3-5b^3

b^3-4b^2=0

Using\:the\:Zero\:Factor\:Principle: if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

So,

b=0,b-4=0

b=0,b=4

Therefore, the solutions are:

b=0,\:b=4

4 0
3 years ago
Read 2 more answers
Help ASAP:Solve : 0.84+91.279
jeka94

Answer:

92.119

Step-by-step explanation:

0.84+91.279=92.119

Hope this helps!

6 0
3 years ago
Read 2 more answers
Midpoint is the center point on the line segment <br> True or false?
Mariana [72]
Your Answer should be True
5 0
3 years ago
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