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adoni [48]
3 years ago
10

Lana draws a triangle( LMN) on the coordinate plane. What is the perimeter of the triangle( LMN)? Round to the nearest unit.

Mathematics
1 answer:
lys-0071 [83]3 years ago
6 0

Answer:

The answer is "25".

Step-by-step explanation:

Please find the graph in the attachment.

Longest \ side= 12

Calculating the triangle two other sides:

=\sqrt{3^2+6^2}\\\\=(9+36)\\\\=45

let

\to \sqrt{45}= 6.7.\\\\\to 6.7\times 2=13.4\\\\\to 13.4+12=25.4 \approx 25

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Select all x values that are solutions to the equation
Nutka1998 [239]

Answer:

The answers are 3 and 5

The only thing u had to do is

x-5=0

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7x-21=0

7x=21

x=3

7 0
2 years ago
Simplify. Write answers with positive exponents only.
allochka39001 [22]

Answer:

The answer to your question is 2⁸x²⁰ y²⁴    or    256x²⁰y²⁴

Step-by-step explanation:

Data

                    (2x³y³)⁴ (2x²y³)⁴

To solve this problem, use the law of exponents.

1.- Use the law of Power of a power rule

                    (2x³y³)⁴ (2x²y³)⁴ =           (2⁴x¹²y¹²) (2⁴x⁸y¹²)      

2.- Use the multiplication rule

                      (2⁴x¹²y¹²) (2⁴x⁸y¹²)  =    2⁸x²⁰ y²⁴

3.- The answer is      2⁸x²⁰y²⁴ or we can simplify more like

                                 256x²⁰y²⁴

7 0
3 years ago
A scientist removed a sample of 39.1 grams of a chemical from a container. The sample was 5 3/4 grams less than 3/10 of the tota
Oksanka [162]

The first thing we must do for this case is to define variables:

x: the total mass of the chemical in the container

y: a sample of a chemical from a container

We have the following equation:

y = (3/10) x - 5 3/4

Then, for y = 39.1 we have:

39.1 = (3/10) x - 5 3/4

Clearing x:

(3/10) x = 39.1 + 5 3/4

(3/10) x = 44.85

x = (10/3) * (44.85)

x = 149.5 grams

Answer:

the total mass in grams of the chemical in the container before the scientist removed the sample of 39.1 grams was:

x = 149.5 grams.

3 0
3 years ago
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Yuki888 [10]

Step-by-step explanation:

First, replace f(x) with y . ...

Replace every x with a y and replace every y with an x .

Solve the equation from Step 2 for y . ...

Replace y with f−1(x) f − 1 ( x ) . ...

Verify your work by checking that (f∘f−1)(x)=x ( f ∘ f − 1 ) ( x ) = x and (f−1∘f)(x)=x ( f − 1 ∘ f ) ( x ) = x are both true.

5 0
4 years ago
HELP PLEASE!!! Picture below!
Lady_Fox [76]

Answer:

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8 0
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