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Vera_Pavlovna [14]
4 years ago
5

Find the distance between (-6,1) and (2,2) round to the nearest hundredth

Mathematics
1 answer:
Contact [7]4 years ago
8 0
The vertical change from one point to the other is 2.  The horiz. change is 8.
Thus, the distance in question is

d = sqrt(2^2+8^2) = sqrt(4+64) = 8.25, rounded to the nearest hundredth.
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