Answer:
7.5
Step-by-step explanation:
You have two triangles with areas of 1.5 and 3 as well as a rectangle with an area of 3
Answer:
![[3, 4]](https://tex.z-dn.net/?f=%5B3%2C%204%5D)
Step-by-step explanation:
{5x + 2y = 23
{13x + 3y = 51
−5⁄13[13x + 3y = 51]
{5x + 2y = 23
{−5x - 1 2⁄13y = 19 8⁄13 >> New Equation
______________________
11⁄13y = 3 5⁄13
_____ ______
11⁄13 11⁄13
[Plug this back into both equations above to get the x-coordinate of 3]; 
I am joyous to assist you anytime.
$5 for reg
$10 for mid
$15-$20 for loud
Something's not quite right here. What do you mean by "N?"
I could and will make assumptions regarding what you meant. (Feel free to correct me if need be.)
Find the equation of a line through (0,2) <span>which is perpendicular to the line y=3x+3. To find the slope of this perpendicular line, take the negative reciprocal of 3 (the slope of the given line). It is -1/3.
Using the point-slope form of the equation of a straight line:
y = (-1/3)x + 2 (answer)</span>
