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aleksklad [387]
3 years ago
13

In scientific notation, the number 39,940,000,000 becomes A. 3.994 × 1010. B. 3.994 × 10–10. C. 39.94 × 109. D. 3994 × 107.

Mathematics
2 answers:
IRINA_888 [86]3 years ago
8 0

you need to move the decimal 10 places to the left to get it between the 3 and 9

 so it would be 3.994 x 10^10

GenaCL600 [577]3 years ago
8 0
<span>39,940,000,000 = 3.994 x 10^10

answer

</span><span>A. 3.994 × 10^10</span>
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In the Ardmore Hotel, 20 percent of the guests (the historical percentage) pay by American Express credit card. (a) What is the
xxMikexx [17]

Answer:

(a) The expected number of guests until the next one pays by American Express credit card is 4.

(b) The probability that the first guest to use an American Express is within the first 10 to checkout is 0.0215.

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of guests until the next one pays by American Express credit card

The probability that a guest paying by American Express credit card is, <em>p</em> = 0.20.

The random variable <em>X</em> follows a Geometric distribution since it is defined as the number of trials before the first success.

The probability mass function of <em>X</em> is:

P(X=x)=(1-p)^{x}p;\ x=0,1,2,3...,\ 0

(a)

The expected value of a Geometric distribution is:

E(X)=\frac{1-p}{p}

Compute the expected number of guests until the next one pays by American Express credit card as follows:

E(X)=\frac{1-p}{p}

         =\frac{1-0.20}{0.20}

         =4

Thus, the expected number of guests until the next one pays by American Express credit card is 4.

(b)

Compute the probability that the first guest to use an American Express is within the first 10 to checkout as follows:

P(X=10)=(1-0.20)^{10}\times0.20

                 =0.1073741824\times 0.20\\=0.02147483648\\\approx0.0215

Thus, the probability that the first guest to use an American Express is within the first 10 to checkout is 0.0215.

3 0
3 years ago
The number of messages arriving at a multiplexer is a Poisson random variable with mean 15 messages/second. Use the central limi
Mila [183]

Answer:

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Step-by-step explanation:

We are given the following information in the question:

The number of messages arriving at a multiplexer is a Poisson random variable with mean 15 messages/second.

Let X be the number of messages arriving at a multiplexer.

Mean = 15

For poison distribution,

Mean = Variance = 15

\text{Standard Deviation} = \sqrt{\text{Variance}} = \sqrt{15} = 3.872

From central limit theorem, we have:

z = \displaystyle\frac{x-n\mu}{\sigma\sqrt{n}}

where n is the sample size.

Here, n = 1 minute = 60 seconds

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P( x > 950) = P( z > \displaystyle\frac{950 - (60)(15)}{\sqrt{(15)(60)}}) = P(z > 1.667)

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Calculation the value from standard normal z table, we have,  

P(x > 950) = 1 - 0.952 = 0.048

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3 0
3 years ago
A hiker maintains an average speed of 3 3/4 km/h. How many kilometers will the hiker walk in: 2 1/6 h
Sunny_sXe [5.5K]
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You will simply have to multiply the time spent walking, 13/6 hours, by the average distance traveled on an hourly basis, 15/4 km/h.

(13*15)/(4*6) = 195/24 = 8,125 km
7 0
3 years ago
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