Answer:
B. Every 16 minutes, 22 more pizzas were set out on the buffet.
Step-by-step explanation:
At 11:00 am, x would be equal to 0, and there would be 15 pizzas on the buffet line. Then, every 8 minutes, 11 more pizzas are added to the buffet line. So in 16 minutes, 22 pizzas will be added to the buffet.
Okay, I think I understand this. Our first step is to solve how long the string is after he used some of it to tie the package. I have a feeling we have to subtract 7/8 - 1/5. Find a least common multiple (in this case, it's 40) and our new fractions are 35/40 and 8/45. Subtract:
35/40 - 8/40 = 27/40.
I don't think this can be simplified down any further as they do not have any common factors. So with that in mind, let's divide 27/40 with 5/1 (5/1 is basically 5 wholes but in fraction version)
When dividing fractions, you want to use the KCF technique (my old math teacher taught me this). Keep the first fraction the same (in this case, 27/40), change the sign from multiplication to division, and flip 5/1 to get it's reciprocal, 1/5. The equation will look like this:
27/40 * 1/5 = 27/200
So each piece is about 27/200 m in length (or 0.135 m in length).
If this is wrong, please let me know, but this is what I got out of this question. I hope this helped you :)
A rational number is 5.3 . It's rational because it can be written as a fraction a/b
- that is 5 3/10 or 53/10.
An irrational number between the 2 values would be √29
Enter this into ur calculator and you'll get an answer like 5.385164807 but this number carries on beyond bounds and can't be written as a fraction a/b It is irrational.
Answer:
h= x/ x+4
Step-by-step explanation:
Move all terms to the left side and set equal to zero, Then set each factor equal to zero.
R = { (x,y): 3x-y=0 }
The condition is 3x=y so that's not going to be any of these things.
R is reflexive if (x,x)∈R for all x. Let's check.
3x - y = 3x - x = 2x ≠ 0 necessarily. NOT REFLEXIVE
R is symmetric if (x,y)∈R → (y,x)∈R. Let's check.
(x,y)∈R so
3x-y = 0
y = 3x
Is (y,x)∈R. That would be true if 3y-x=0
3y - x = 3(3x) - x = 8x ≠ 0 necessarily NOT SYMMETRIC
R is transitive if (x,y)∈R and (y,z)∈R → (x,z)∈R. Let's check.
3x-y = 0 so y=3x
3y-z = 0 so z=3y = 9x
3x - z = 3x - 9x = -6x ≠ 0 necessarily NOT TRANSITIVE
