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almond37 [142]
3 years ago
7

Question 12 1 pts If the population of a country is reported in the year 1990 as 471.56 million and in the year 2000 as 492.53 m

illion, what will the population be in the year 2015 (round your answer to the nearest hundredths)? 767.15 million 831.31 million 526.39 million 275.18 million
Mathematics
1 answer:
I am Lyosha [343]3 years ago
3 0

Answer:

  526.39 million

Step-by-step explanation:

The exponential equation can be written as ...

  p(t) = 471.56(492.53/471.56)^(t/10)

Then p(25) ≈ 525.75 . . . . million

__

The closest answer choice is 526.39 million.

__

<em>Comment on the answer choice</em>

Reverse-engineering the answer, we find it was computed using the exponential equation ...

  p(t) = 471.56e^(0.0044t)

  p(25) = 471.56·1.116278 ≈ 526.39

The k factor in the exponent is <em>inappropriately rounded</em> from 0.004350903. You cannot use a 2-significant-figure constant to arrive at an accurate 5-significant-figure answer.

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