All categories

2 years ago

Someone please help

Mathematics

1 answer:

Natasha2012 [34]2 years ago

6 0

Correct Work

4x+8 +3(x-4)

4x +8 + 3x-12

4x+3x+8 -12

7x -4

Mistake Made

3 wasn't multiplied by the 4 in the bracket
Like terms wasn't combined in the working out
The answer was supposed to be -4, 8-4= -4

You might be interested in

ASAP PLZZZ The axis of symmetry for the graph of the function f start bracket x end bracket equals one-quarter x square plus b x

Lilit [14]

Answer:

$b=-3$

Step-by-step explanation:

The given function is $f(x)=\frac{1}{4}x^2+bx+10$ .

When we compare to $ax^2+bx+=0$ , we have

$a=\frac{1}{4}$ and c=10

The equation of the axis of symmetry of a vertical parabola is:

$x=-\frac{b}{2a}$

Also from the question the axis of symmetry is x=6

We substitute the values to get:

$6=-\frac{b}{2*\frac{1}{4}}$

$6=-\frac{b}{\frac{1}{2}}$

$b=-\frac{1}{2}*6$

$b=-3$

7 0

2 years ago

Read 2 more answers

Use the diagram to answer the question

Ivan

Answer:

148

Step-by-step explanation:

a line (cd) is 180°

cba + and must be 180°

180-33=148

8 0

2 years ago

The vertices of a triangle ABC are A(7, 5), B(4, 2), and C(9, 2). What is measure of angle ABC? 30° 45° 56.31° 78.69°

GenaCL600 [577]

The measure of angle ABC is 45°

Explanation

Vertices of the triangle are: A(7, 5), B(4, 2), and C(9, 2)

According to the diagram below....

Length of the side BC (a) $=\sqrt{(4-9)^2+(2-2)^2}= \sqrt{25}= 5$

Length of the side AC (b) $= \sqrt{(7-9)^2 +(5-2)^2}= \sqrt{4+9}=\sqrt{13}$

Length of the side AB (c) $= \sqrt{(7-4)^2 +(5-2)^2} =\sqrt{9+9}=\sqrt{18}$

We need to find ∠ABC or ∠B . So using Cosine rule, we will get...

$cosB= \frac{a^2+c^2-b^2}{2ac} \\ \\ cos B= \frac{(5)^2+(\sqrt{18})^2-(\sqrt{13})^2}{2*5*\sqrt{18} }\\ \\ cosB= \frac{25+18-13}{10\sqrt{18}} =\frac{30}{10\sqrt{18}}=\frac{3}{\sqrt{18}}\\ \\ cosB=\frac{3}{3\sqrt{2}} =\frac{1}{\sqrt{2}}\\ \\ B= cos^-^1(\frac{1}{\sqrt{2}})= 45 degree$