Given
A rectangular park of length 60 m breadth 50 m encloses with volleyball court of length 18 m and breadth 10 m.
To find:
The area of the park excluding the court at the rate of Rs 110 per square meter.
Solution:
Area of a rectangle is:
Area of whole park is:
Area of volleyball court is:
Now, the area of the park excluding the court is:
Therefore, the area of the park excluding the court is 2820 square meter.
First, plug in the given point into y=mx +b to find b (the y-intercept of the line). Use the same slope (m) in the equation since parallel lines have the same slope (3 in this case).
-1 = 3(4) +b
-1 = 12 + b Subtract 12 to both sides.
-13 = b
Now, put your m and b into y=mx+b.
The final answer/equation of your line is:
y=3x -13
Anything over 12/6 will be greater than 4/2 such as 19/6 or 28/6
Second one
1/16
3/8 divided by 1/6=1/16
