Width = x
Length = x+18
Assuming the table is rectangular:
Area = x(x + 18)
Therefore:
x(x + 18) <span>≤ 175
x^2 + 18x </span><span>≤ 175
Using completing the square method:
x^2 + 18x + 81 </span><span>≤ 175 + 81
(x + 9)^2 </span><span>≤ 256
|x + 9| </span><span>≤ sqrt(256)
|x + 9| </span><span>≤ +-16
-16 </span>≤ x + 9 <span>≤ 16
</span>-16 - 9 ≤ x <span>≤ 16 - 9
</span>-25 ≤ x <span>≤ 7
</span><span>
But x > 0 (there are no negative measurements):
</span><span>
Therefore, the interval 0 < x </span><span>≤ 7 represents the possible widths.</span><span>
</span>
Answer:
x = 25
Step-by-step explanation:
Those 2 angles together form a straight line which is equal to 180°. So you can set up an equation:
3x + 18 = 93
-18 -18
3x = 75
Divide both sides by 3
x = 25
There is no solution to this
A^2 +b^2 = c^2
a= wall
b = ground (18)
c = ladder (25)
a^2 + 18^2 = 25^2
a^2 + 324 = 625
a^2 = 301
a = 17.349
