Answer:
side - equation - measurement
1st side - 2s - 65 - 55cm
2nd side - s - 60cm
3rd side - s - 10 - 50cm
Step-by-step explanation:
total = 165
side - s
1st side = 2s - 65
2nd side = s
3rd side = s - 10
1st side + second side + 3rd side = 165
2s - 65 + s + s - 10 = 165
2s + s + s - 65 - 10 = 165
4s - 75 = 165
4s = 165+ 75
4s = 240
<u>s = 60</u>
<em>1st side = 2s - 65</em>
<em> = 2(60) - 65</em>
<em> = 120 - 65</em>
<em> </em><u><em>= 55cm</em></u>
<em>2nd side = s</em>
<em> =</em><u><em> 60cm</em></u>
<em>3rd side = s - 10</em>
<em> = 60 - 10</em>
<em> = </em><u><em>50cm</em></u>
3rd side is represented by<u> s - 10</u> as it is less than the second side by 10cm hence taking away the 10 from the side forming the equation <u>s - 10</u>
<u><em /></u>
Complete question :
The denarius was a unit of currency in ancient Rome. Suppose it costs the Roman government 10 denarius per day to support 3 legionaries and 3archers. It only costs 3 denarius per day to support one legionary and one archer. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?
Answer:
No unique solution
Step-by-step explanation:
Given that:
Cost of supporting 3 legion aries and 3 archers = 10 denarius daily
Cost of supporting one legionary and one archer = 3 denarius
Let:
Legionaries = l ; archers = a
Equation for the first sentence :
3l + 3a = 10 - - - (1)
Second sentence :
l + a = 3 - - - - - (2)
From (2)
l = 3 - a
Substituting l = 3 - a into (1)
3(3 - a) + 3a = 10
9 - 3a + 3a = 10
9 - 0 = 10
The variable cancels out, Hence, ( there is no unique solution to find the cost of each soldier)
Answer:
Step-by-step explanation:
No it is not a polynomial
Answer:
The answer is 13/6
Step-by-step explanation:
9/6 + 6/9
9/6 = 3/2
6/9 = 2/3
Now,
3/2 + 2/3
Cross Multiply
3 × 3 + 2 × 2/2 × 3
9 + 4/6 = 13/6
Thus, The answer is 13/6
<u>-TheUnknownScientist</u><u> 72</u>
I think it may be this one 40×9=360