What’s the value of y?

Mathematics

1 answer:

stepan [7]4 years ago

6 0

I can’t tell where Y is, sorry

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An amusement park sells adult tickets and children’s tickets, with adults tickets costing $5 and children’s tickets costing $3.

Katarina [22]

Answer:

Nine

Step-by-step explanation:

3 dollars for children tickets : x

5 dollars for adult tickets: y

Equation is:

3x+5y=57

Where 57 is the total amount spent

x+y=15

where 15 is the total number of tickets bought

3x+5y=57

5(x+y)=5(15)

___________________

3x+5y=57

5x+5y=75

minus the equations top to bottom=

-2x= -18

x= -18/(-2)

x=9

He bought a total of 9 children tickets

7 0

3 years ago

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How do I do this plz help me

LenaWriter [7]

Jane has half as much as Elaine at first. The answer is 12, but I honestly just kept using random numbers. After spending 4, Jane has 8 and Elaine has 20.(12 times 2) - 4

6 0

3 years ago

You and two friends (Adam and Alana) will only play a game if it is fair for all three of you. The game your friend has proposed

scZoUnD [109]

Yes, the game was fair and no one had a better advantage.

4 0

3 years ago

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State the vertical asymptote of the rational function. f(x) =((x-9)(x+7))/(x^2-4)

Lubov Fominskaja [6]

$D:x^2-4\not=0\\
D:x^2\not=4\\
D:x\not=-2 \wedge x\not =2\\\\
\displaystyle
\lim_{x\to-2^-}\dfrac{(x-9)(x+7)}{x^2-4}=\\
\dfrac{(-2-9)(-2+7)}{(-2^-)^2-4}=\dfrac{-11\cdot5}{4^+-4}=\dfrac{-55}{0^+}=-55\cdot\infty=-\infty\\
\dfrac{(-2-9)(-2+7)}{(-2^+)^2-4}=\dfrac{-11\cdot5}{4^--4}=\dfrac{-55}{0^-}=-55\cdot(-\infty)=\infty
$

$\displaystyle
\lim_{x\to2^-}\dfrac{(x-9)(x+7)}{x^2-4}=\\
\dfrac{(2-9)(2+7)}{(2^-)^2-4}=\dfrac{-7\cdot9}{4^--4}=\dfrac{-63}{0^-}=-63\cdot(-\infty)=\infty\\
\dfrac{(2-9)(2+7)}{(2^+)^2-4}=\dfrac{-7\cdot9}{4^+-4}=\dfrac{-63}{0^+}=-63\cdot\infty=-\infty\\$

So, the vertical asymptotes are $x=\pm 2$