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Artyom0805 [142]
3 years ago
5

I need help with algebra!!! Can someone help me?????????????

Mathematics
1 answer:
marta [7]3 years ago
7 0
Yes;what's your question?
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You roll 2 dice. What is the probability of getting two 5's?
eduard
The coment before me is super funny lol
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3 years ago
Can someone help with this???
sineoko [7]

Answer:

The last one

Step-by-step explanation:

Because 0 < -2 -2, 0 <-4. It is not a true statement. It tell you that the middle one is wrong. The first one is wrong to because there are no equal sign.

3 0
3 years ago
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What is the answer to 3/7w-11=4/7w
sladkih [1.3K]
For this equation first you should add +11 on both sides and the add -4/7w so you will have: 
3/7w- 4/7w = 11 ⇒ -1/7w = 11 ⇒ w = 11* -7 = -77 so the answer is:
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6 0
3 years ago
Which expression is equivalent to<br> logbase12 ((1/2)/8w)?
Lunna [17]

\bf \begin{array}{llll} \textit{logarithm of factors} \\\\ log_a(xy)\implies log_a(x)+log_a(y) \end{array}~\hfill \begin{array}{llll} \textit{Logarithm of rationals} \\\\ log_a\left( \frac{x}{y}\right)\implies log_a(x)-log_a(y) \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \log_{12}\left( \cfrac{~~\frac{1}{2}~~}{8w} \right)\implies \begin{array}{llll} \log_{12}\left( \frac{1}{2} \right)&-&\log_{12}(8w)\\\\ \log_{12}(1)-\log_{12}(2)&-&[\log_{12}(8)+\log_{12}(w)] \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \log_{12}(1)-\log_{12}(2)-\log_{12}(8)-\log_{12}(w)~\hfill

7 0
3 years ago
A box of cereal states that there are 96 calories in a 3/4
IgorC [24]

Answer:

112 calories per cup

Step-by-step explanation:

Let x = unit rate for calories per cup,

Then (3/4)*x = 84

and x = 84*(4/3) = 112 calories per cup

3 0
3 years ago
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