Answer:
I guess that you want to know the transformations:
We start with:
f(x) = y = 4*x + 3
a)the transformed function is:
f(x) = y = -4*x - 3
So the sign changed.
This means that we go from (x, y) to (x, - y)
This is a reflection over the x-axis which changes the sin of the y component.
b) Now we go to f(x) = 4*x + 3
So the coefficient in the leading term changed.
This is a horizontal contraction:
A horizontal contraction of factor K for the function g(x) is: g(K*x)
In our case, we have:
f(K*x) = 4*(k*x) + 3 = x + 3
4*k*x = x
4*k = 1
k = 1/4
Then the transformation is an horizontal contraction of scale factor 1/4.
Answer:
See the proof below.
Step-by-step explanation:
Assuming this complete question: "For each given p, let Z have a binomial distribution with parameters p and N. Suppose that N is itself binomially distributed with parameters q and M. Formulate Z as a random sum and show that Z has a binomial distribution with parameters pq and M."
Solution to the problem
For this case we can assume that we have N independent variables
with the following distribution:
bernoulli on this case with probability of success p, and all the N variables are independent distributed. We can define the random variable Z like this:
From the info given we know that
We need to proof that
by the definition of binomial random variable then we need to show that:


The deduction is based on the definition of independent random variables, we can do this:

And for the variance of Z we can do this:
![Var(Z)_ = E(N) Var(X) + Var (N) [E(X)]^2](https://tex.z-dn.net/?f=%20Var%28Z%29_%20%3D%20E%28N%29%20Var%28X%29%20%2B%20Var%20%28N%29%20%5BE%28X%29%5D%5E2%20)
![Var(Z) =Mpq [p(1-p)] + Mq(1-q) p^2](https://tex.z-dn.net/?f=%20Var%28Z%29%20%3DMpq%20%5Bp%281-p%29%5D%20%2B%20Mq%281-q%29%20p%5E2)
And if we take common factor
we got:
![Var(Z) =Mpq [(1-p) + (1-q)p]= Mpq[1-p +p-pq]= Mpq[1-pq]](https://tex.z-dn.net/?f=%20Var%28Z%29%20%3DMpq%20%5B%281-p%29%20%2B%20%281-q%29p%5D%3D%20Mpq%5B1-p%20%2Bp-pq%5D%3D%20Mpq%5B1-pq%5D)
And as we can see then we can conclude that 
Answer:
i
Step-by-step explanation:
This is the answer you get when you square and you get a negative number.
Answer:
362880
Step-by-step explanation:
You have to subtract the two people who are already doing something in line so you would do 11-2 which equals 9. Then you would do 9 mPr 9 which gives you an answer of 362,880.