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Semmy [17]
3 years ago
10

The two square pyramids are similar. The side length of the smaller pyramid is 3/4 the side length of the larger pyramid.Which f

raction represents the ratio of the base area of the smaller pyramid to the base area of the larger pyramid?
A.9/16
B.3/4
C.4/3
D.16/9

Mathematics
2 answers:
vagabundo [1.1K]3 years ago
8 0

The correct answer is:

A. \frac{9}{16}

The fraction represents the ratio of the base area of the smaller pyramid to the base area of the larger pyramid.

|Huntrw6|

vichka [17]3 years ago
7 0
The answer is <span>A.9/16.

The ratio of areas of two similar squares is the square of the ratios of their similar side lengths. Since </span><span>the ratio of the smaller side length to the larger side length is 3/4, the ratio of areas of two similar squares is:
(3/4)</span>² = 3²/4² = 9/16.
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The hour hand of a clock moves −30° every hour. How many degrees does it move in 2&amp;1/5 hours?
ad-work [718]

Answer:

ok is very easy

Step-by-step explanation:

so 1/5 of an hour is 12 mins

and 2 is 2 hrs so that 120 mins

now add 120+12=132

132 x -30 degrees

The answer to that is 132 x -30 =

-3960 sorry if its wrong and if you get a second try put -69.1150384 rad

I think sorry if you get it wrong have a good day  

6 0
3 years ago
Max was on vacation twice as long is Jared and half as long as Wesley. The boys were on vacation a total of three weeks. How man
nasty-shy [4]
To begin with, the question is asking for the answer in days, so let's change 3 weeks to days. There are 7 days in 1 week; 3 weeks times 7 days = 21 days.
21 total days of vacation.

Max + Jared + Wesley = 21 days
(Let's use the first letter of their name to represent their vacation time)

M + J + W = 21 [This is the equation we'll be coming back to]

Now, we can use the clues given in the question to have an equation for each variable/boy. 

Max was on vacation twice as long as Jared. We can interpret this as  M= 2J Max was on vacation only half as long as Wesley. We can interpret this as M = (1/2)W.

So far we have these three equations: M + J + W = 21M = 2J M = (1/2)W

To have an equation for each individual boy, we must rearrange the last two equations in the list.

First, M = 2J.
Divide both sides by 2
M/2 = 2J/2
(1/2)M = J

Second, <span>M = (1/2)W
Multiply both sides by 2
2M = W

New equations:
</span><span>M + J + W = 21 [From the old list]
</span>J = (1/2)W
W = 2M

Now we can substitute the last two equations into the first one. 
M + J + W = 21
M + (1/2)W + 2M = 21
[Combine Like Terms]
<span>(7/2)M = 21 
</span>
Then, solve for M (Max's vacation days):
Multiply both sides by 2/7
(\frac{2}{7})* (\frac{7}{2}m)= (\frac{2}{7})*(21)
M = 6

Now we know Max was on vacation for 6 days.

If Max was on vacation twice as long as Jared, that means Jared was on vacation HALF as long as Max.

So...
<span>J = (1/2)M 
J = (1/2) * 6
J = 3
Jared was on vacation for 3 days 
</span>
Wesley was on vacation twice as long as Max so...  W = 2M 
W= 2*6
W = 12
Wesley was on vacation for 12 days. 

Let's double check our answer:
M + J + W = 21 days<span>6 + 3 + 12 = 21   
The numbers work out so the math is correct. Hope this helps and makes sense!</span>
6 0
3 years ago
A certain isotope decays so that the amount A remaining after t years is given by: A = A0 · e ^-0.03t where A0 is the original a
Katena32 [7]
<span>Ending Amt = Bgng Amt * e ^-0.03t
In this equation, the "-0.03" is the decay factor or "k"
We can now solve for half-life by this equation:
</span>t = <span>(<span>ln [y(t) ÷ a]<span>)<span> ÷ -k  (we can say beginning amount = 200 and ending amount = 100
</span></span></span></span>t = <span>(<span>ln [200 ÷ 100]<span>)<span> ÷ -k
</span></span></span></span>t = <span>(<span>ln [2]<span>)<span> ÷ -k
</span></span></span></span>t = 0.69314718056<span> ÷ --.03
t =</span><span><span><span> 23.1049060187 </span>
about 23 years
</span></span>
7 0
3 years ago
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The answer is 17 and 31
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8 and 5 and I hate IXL ugh
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