Question

Find cot theta. (-6,-3sqrt(5)

Answer 1

0  Pretend that is theta XD

cot 0 = $\frac{1}{tan0}$

Find tan 0.

tan 0 = $\frac{y}{x}$

tan 0 = $\frac{-3\sqrt{5}}{-6}$

tan 0 = $\frac{\sqrt{5}}{2}$

cot 0 = $\frac{1}{tan0}$

cot 0 = $\frac{1}{\frac{\sqrt{5} }{2} }$    

Multiply 2/√5 to the numerator and the denominator (or multiply the reciprocal of the denominator to the top and bottom of the fraction)

cot 0 = $\frac{1}{\frac{\sqrt{5}}{2} } (\frac{\frac{2}{\sqrt{5}} }{\frac{2}{\sqrt{5}}} )$

cot 0 = $\frac{2}{\sqrt{5}}$  

Multiply √5 to the numerator and the denominator

cot 0 = $\frac{2}{\sqrt{5}} (\frac{\sqrt{5} }{\sqrt{5} })$

cot 0 = $\frac{2\sqrt{5}}{5}$