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timama [110]
3 years ago
12

Find cot theta. (-6,-3sqrt(5)

Mathematics
1 answer:
cupoosta [38]3 years ago
5 0

0  Pretend that is theta XD


cot 0 = \frac{1}{tan0}


Find tan 0.

tan 0 = \frac{y}{x}

tan 0 = \frac{-3\sqrt{5}}{-6}

tan 0 = \frac{\sqrt{5}}{2}


cot 0 = \frac{1}{tan0}

cot 0 = \frac{1}{\frac{\sqrt{5} }{2} }    

Multiply 2/√5 to the numerator and the denominator (or multiply the reciprocal of the denominator to the top and bottom of the fraction)

cot 0 = \frac{1}{\frac{\sqrt{5}}{2} } (\frac{\frac{2}{\sqrt{5}} }{\frac{2}{\sqrt{5}}} )

cot 0 = \frac{2}{\sqrt{5}}  

Multiply √5 to the numerator and the denominator

cot 0 = \frac{2}{\sqrt{5}} (\frac{\sqrt{5} }{\sqrt{5} })

cot 0 = \frac{2\sqrt{5}}{5}


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(1,-7) with a slope of -5 as an equation
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y=mx+b

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y=-5x+b

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7 0
2 years ago
Look at the figure. How can you prove ∆ABD and ∆ACD are congruent?
Levart [38]

Answer:

Options (C)

Step-by-step explanation:

For the congruence of the triangles ΔADB and ΔADC,

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1). AB ≅ AC                                   1). Given

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3). ∠BAD ≅ ∠CAD                       3). Given

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7 0
3 years ago
A researcher surveyed 220 residents of a city about the number of hours they
olga55 [171]

Answer:

Margin of error of 0.0485 hours.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

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In which \sigma is the standard deviation of the population and n is the size of the sample.

In this question:

\sigma = 0.35, n = 220

The margin of error is of:

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M = 1.96\frac{0.35}{\sqrt{200}}

M = 0.0485

Margin of error of 0.0485 hours.

5 0
2 years ago
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The answer would be 1
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irakobra [83]

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