Solve the equation for the indicated variable dfg=h; f
1 answer:
<em>div</em><em>ide</em><em> </em><em>the</em><em> </em><em>wh</em><em>ole</em><em> </em><em>eq</em><em>uation</em><em> </em><em>by</em><em> </em><em>dg</em><em> </em><em>as</em><em> </em><em>sh</em><em>own</em><em> </em><em>b</em><em>elow</em>
<em></em>
<em>then</em><em> </em><em>you</em><em> </em><em>cancel</em><em> </em><em>out</em><em> </em><em>de</em><em> </em><em>dg</em><em>,</em><em> </em><em>leavi</em><em>ng</em><em>;</em>
<em></em>
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Answer:
The probability that the cost for someone's dog is higher than for the cat is 33.2%.
Step-by-step explanation:
With the data given, we know that the difference in cost of medical care of dogs and cats have a normal distribution with μ=-20 and σ=46.
To know the probability of the cost for the dog is higher than the cat, we have to calculate the probability of P(d>0).
Then we have to calculate z, and look up in a standarized normal distribution table.
Calculate z:
The probability of the difference being higher than 0, we have:
We can say that the probability that the cost for someone's dog is higher than for the cat is 33.2%.