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3 years ago

Evaluate the numerical expression 10 + 36 ÷9

Mathematics

2 answers:

Molodets [167]3 years ago

6 0

36 / 9 equals 4 so the problem is basically 10 + 4 which is 14.

meriva3 years ago

6 0

Let's find the result of the numerical expression:

Remember: 1º) multiplication and division; 2º) addition and subtraction

x = 10 + 36 / 9

x = 10 + 4

x = 14

This numerical expression has a value of 14.

Hope it helps.

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ILL GIVE 50 POINTS PLS Trey has plastic cubes stored in a box that measures 3 ft long, 2 1/2ft wide, and 2 ft tall. The edge len

Triss [41]

Volume of the box

LBH
3(2.5)(2)
6(2.5)
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7 0

2 years ago

PLEASE I NEED HELP

klemol [59]

Answer: 0.25 feet

Step-by-step explanation:

Given: Jonathon has paper strips that are all equal in length.

Let x be the length of each paper strip.

Since John lines them up end to end, the length of the line of paper strips= 3 feet

Also total strips used= 12

Therefore, length of line of strips= $12x=3\ feet$

$\\\Rightarrow\ x=\frac{1}{4}\ feet\\\Rightarrow\ x= 0.25\ feet$

hence, if Jonathan is correct then the length of each strip will be 0.25 feet.

8 0

3 years ago

High in the rocky mountains, a biology research team has drained a lake to get rid of all fish. After the lake was refilled, the

nadya68 [22]

Answer:

Step-by-step explanation:

High in the Rocky Mountains, a biology research team has drained a lake to get rid of all fish. After the lake was refilled, they stocked it with an endangered species of Greenback trout. Of the 2000 Greenback trout put into the lake 400 were tagged for later study. An electroshock method is used on individual fish to get a study sample. However, this method is hard on the fish. The research team wants to know the smallest number of fish that must be electroshocked to be at least 50% sure of getting a sample of two or more tagged trout.

we have to find out smallest number fish (n) that must be electroshoked to be atleast 50% &

species of Greenback trout of the 2000 greenback trout put into the lake 400

6 0

3 years ago

You have been tasked with filling 4 ounce and 3 ounce bags from a 41 ounce container of candy.

Alchen [17]

Answer:

A. 3 possible combinations

B. 8 4-ounce's bags and 3 3-ounce's bags

C. 2 4-ounce's bags and 11 3-ounce's bags

D. 8 4-ounce's bags and 3 3-ounce's bags

E. All solutions offer the same revenue.

Step-by-step explanation:

You have been tasked with filling 4 ounce and 3 ounce bags from a 41 ounce container of candy. Let x be the number of 4 ounce bags and y be the number of 3 ounce bags. Then

$4x+3y=41.$

A. Find all integer solutions:

When x=0, then 3y=41 - impossible, because 41 is not divisible by 3.

When x=1, then 3y=37 - impossible, because 37 is not divisible by 3.

When x=2, then 3y=33, y=11 - possible.

When x=3, then 3y=29 - impossible, because 29 is not divisible by 3.

When x=4, then 3y=25 - impossible, because 25 is not divisible by 3.

When x=5, then 3y=21, y=7 - possible.

When x=6, then 3y=17 - impossible, because 17 is not divisible by 3.

When x=7, then 3y=13 - impossible, because 13 is not divisible by 3.

When x=8, then 3y=9, y=3 - possible.

When x=9, then 3y=5 - impossible, because 5 is not divisible by 3.

When x=10, then 3y=1 - impossible, because 1 is not divisible by 3.

You get 3 possible combinations.

B. 1. 2 + 11 = 13,

2. 5 + 7 = 12,

3. 8 + 3 = 11.

The minimal number of bags is 11.

C. 1. 2·7+11·5=69 cents

2. 5·7+7·5=70 cents

3. 8·7+3·5=71 cents

The cheapest is 1st solution.

D. 1. 2·6+11·5=67 cents

2. 5·6+7·5=65 cents

3. 8·6+3·5=63 cents

The cheapest is 3rd solution.

E. 1. 2·2+11·1.50=$20.50

2. 5·2+7·1.50=$20.50

3. 8·2+3·1.50=$20.50

All solutions offer the same revenue.

5 0

3 years ago

farmer ryan has corn field that is nearly a rectangle. the length is five meters more than the width. the perimeter is about 210

Tcecarenko [31]

Farmer ryan has a corn feild that is in the shape of a rectangle. The length is five meters more than the width. The perimeter is 210 meters.

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Question 1123428: A bucket is in the shape of a truncated cone.The height of the bucket is 45 cm,and the diameters of the top and the bottom surfaces are 56 cm and 14 cm respectively.Find the the quantity (in litres) of the water the bucket can hold.

Answer by Boreal(9049) About Me (Show Source):

You can put this solution on YOUR website!

V=(1/3)(r1^2+r1r2+r2^2)h*pi

=(1/3)*45*(28^2+196+49)*pi

=15(1029)*pi

A piece of paper is in the shape of a sector of a circle whose radius is 12 cm and the central angle of the sector is 120 degree.

It is rolled to form a cone of the biggest possible capacity.

Find the capacity of cone.

Find the total area of the sector

A = 120%2F360*pi%2A12%5E2

A = 150.8 sq/cm, this is surface area of the cone

Surface area (SA) of a cone without the end formula

The slant length (s) = the radius of the paper; 12 cm

pi%2Ar%2As+=+SA

pi%2Ar%2A12+=+150.8 , find r, the radius of the cone

r = 150.8%2F%2812%2Api%29

r = 4 cm is the radius

find the height of the cone

h = sqrt%28s%5E2-r%5E2%29

h = sqrt%2812%5E2-4%5E2%29

h = 11.3 cm is the height of the cone

Find the capacity (volume)

V+=+1%2F3*+pi%2Ar%5E2%2Ah

V = 1%2F3*pi%2A4%5E2%2A11.3

V = 189.33 cu/cm

6 0

3 years ago