Answer:
30,240 ways
Step-by-step explanation:
This question is bothered on permutation. Permutation has to do with arrangement.
If there are 10 computers and 5 students, the number of ways students will sit at the computers if no computer has more than one student can be expressed as;
10P5 = 10!/(10-5)!
10P5 = 10!/(5)!
10P5 = 10*9*8*7*6*5!/5!
10P5 = 10*9*8*7*6
10P5 = 30,240
Hence the number of ways is 30,240 ways
The answer is 56.
I know this because...
<span>-6 + {14 + 2 [60 − 9(1 + 3)]}
-6 + </span>{14 + 2[60 − 9(4)]}
-6 + {14 + 2[60 − 36]}
-6 + {14 + 2[24]}
-6 + {14 + 48}
-6 + {62}
-6 + 62 = 56
The one under the one you picked but im not 100% sure
The answer if I am correct should be C. 6, since if you divide forty-eight by two you get twenty-four. Twenty-four divided by four equals six, and twenty-four divided by three equals eight, eight is the number that would be the remaining amount of days. Hope this helps you and have an amazing day!
