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Gelneren [198K]
3 years ago
11

I have some geometry questions today!

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
5 0

Answer:

<h3>Question 7</h3>

<u>Arc LM has length of:</u>

  • LM = 2πr*72/360
  • LM = 2π*1*1/5
  • LM = 2π/5
<h3>Question 8</h3>

<u>Area of the given sector:</u>

  • πr²*θ/360 =
  • x²π*(360 - 75)/360 =
  • x²π(19/24) =
  • 19πx²/24

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The perimeter of a rectangle is 54 meters. One side is three meters less than four times the length of the other side. Find the
Elenna [48]

Answer:

6 and 21 meters long

Step-by-step explanation:

You make an equation from what you got (there are 2 widths and 2 lengths)

2(4w-3)+2w=54---->10w-6=54---> 10w=60 ----> w=6 ---> plug in the rest and you get 21 as the length.

or... make W+L=28 and guess and check!!! takes longer but works!

7 0
3 years ago
Find the measure of arc DHG
const2013 [10]

Answer:

128

Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Lisa is 53 3 4 inches tall. Joey is 1 1 2 inches shorter than Lisa and Jane is 1 1 5 inches shorter than Joey. How tall is Jane?
tester [92]

Answer: Jane's height =  51\dfrac{1}{20}\text{ inches}

Step-by-step explanation:

Given: Lisa's height = 53\dfrac34\text{ inches}=\dfrac{4\times53+3}{4}\text{ inches}

=\dfrac{215}{4}\text{ inches}

Joey's height = \dfrac{215}4-1\dfrac12 inches

=\dfrac{215}4-\dfrac32\\\\=\dfrac{215-6}{4}\\\\=\dfrac{209}{4}\text{ inches}

Jane's height = \dfrac{209}{4}-1\dfrac15 inches

=\dfrac{209}{4}-\dfrac{6}{5}\\\\=\dfrac{209\times5-6\times4}{20}\\\\=\dfrac{1045-24}{20}\\\\=\dfrac{1021}{20}\\\\=51\dfrac{1}{20}\text{ inches}

Hence, Jane's height = 51\dfrac{1}{20}\text{ inches}

3 0
3 years ago
What is the answer?
Amanda [17]
B seems right.
I think
4 0
3 years ago
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