The sum of the angles of a quadrilateral is 360 degrees. So P+Q+R is 206, 360 - 206 = 154 degrees, the measure of angle S.
The four triangles, AQB, BRC, CSD, and DPA are all isosceles. So angle QBA = angle BAQ, etc. We find QBA = (180-24)/2 or 78 degrees.
RBC = (180-114)/2 = 33 degrees.
180 - (78 + 33) is the measure of angle B: 69 degrees.
The student should be able to see how to calculate the missing information from this.
Answer:
50°
Step-by-step explanation:
Let measure of one equal side be x.
80° +x +x = 180°[ sum of interior angle of triangle is 180°]
= 2x = 180° -80°
= x = 100°/2
=x = 50°
The unknown value can be called x.
3(2x +4) = 72
6x +12 = 72
72 - 12 = 6x
6x = 60
x = 6x / 6
x = 10
Hope This Helps You!
<span>Good Luck Studying :)</span>
Answer : 32
( angles of a triangle add up to 180)
