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3 years ago

What is a square root?

Mathematics

2 answers:

Alex777 [14]3 years ago

8 0

Answer:

a number which produces a specified quantity when multiplied by itself.

Step-by-step explanation:

7 is a square root of 49"

yan [13]3 years ago

5 0

A sqaure foot is a number which produces a specified quantity when multiplied by itself.

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Convert 3,200,000 to a scientific notation.

tia_tia [17]

3,200,00 converted to scientific notation is 3.2 x 106

7 0

3 years ago

Read 2 more answers

A system of two equations has no solution. One equation is -15x+y=18.

DerKrebs [107]

If you multiply the original equation by 3 you get -45x+3y=54, which is the exact same as A, therefore they have infinite solutions.

5 0

3 years ago

1) Simplify the following expressions: a) sin²108° + sin² 18°

abruzzese [7]

Note that

108° = 90° + 18°

sin(108°) = sin(90° + 18°) = sin(90°) cos(18°) + cos(90°) sin(18°) = cos(18°)

Then

sin²(108°) + sin²(18°) = cos²(18°) + sin²(18°) = 1

by the Pythagorean identity.

8 0

2 years ago

What are like terms in math no looking it up thx

maksim [4K]

Answer:

<h2>See below</h2>

Step-by-step explanation:

Terms are variables in math.

For example: 5x + 6y = is NOT like becuase x and y equal different things

4x + 2x = is like becuase x equals the same number in both

The reason we care about like terms is because we can simplify like terms.

4x + 2x simply equals 6x.

I'm always happy to help :)

5 0

3 years ago

If the initial velocity stays the same, but the height the projectile is launched from changes , how would the amount of time ch

pickupchik [31]

Answer:

Part A

The height to which the projectile reaches is given by the following formula;

$\Delta y = y-y_0 = v_{0y} \times t-\dfrac{1}{2} \times g \times t^2$

Where;

$v_{0y}$ = The initial velocity of the projectile = Stays the same

y = The height the projectile reaches

y₀ = The height from which the projectile is launched

g = The acceleration due to gravity

t = The time taken

Given that the projectile has the same initial velocity, the variation of Δy with time, 't', will be the same when the project is launched from a different height, and the time change that it takes for the projectile to reach the maximum height will be the same for the previous launch height

Part B

From the change in eight of the projectile, Δy = y - y₀, the maximum height reached, 'y', is therefore given as follows;

y = Δy + y₀

The maximum height will increase by 'y₀', where 'y₀' is the difference between new height and the previous height, $y_i$

That is, if y₀ > $y_i$ , the maximum height reached increases and if y₀ < $y_i$ , y₀ will be added as y = Δy - y₀ and the maximum height reached decreases

Step-by-step explanation:

6 0

2 years ago