13. Given: AB//DC, Prove: Triangle ABE is congruent to Triangle DCE please help! I am so far behind on my work right now I will
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Answer:
B.
Hope this helped. A brainliest would be very much appreciated. (I need 4 brainliest so I can level up) :)
The terms of an arithmetic progression, can form consecutive terms of a geometric progression.
- The common ratio is:
- The general term of the GP is:
The nth term of an AP is:
So, the <em>2nd, 6th and 8th terms </em>of the AP are:
The <em>first, second and third terms </em>of the GP would be:
The common ratio (r) is calculated as:
This gives
The nth term of a GP is calculated using:
So, we have:
Read more about arithmetic and geometric progressions at: