The solution to given system of equations are (x, y) = (4, 2)
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
2x + 3y = 14 ---------- eqn 1
3x - 4y = 4 --------- eqn 2
We have to solve the given system of equations
We can solve the above system of equations by elimination method
<em><u>Multiply eqn 1 by 3</u></em>
3(2x + 3y = 14)
6x + 9y = 42 --------- eqn 3
<em><u>Multiply eqn 2 by 2</u></em>
2(3x - 4y = 4)
6x - 8y = 8 ----------- eqn 4
<em><u>Subtract eqn 4 from eqn 3</u></em>
6x + 9y = 42
6x - 8y = 8
( - ) --------------
9y + 8y = 42 - 8
17y = 34
<h3>y = 2</h3>
<em><u>Substitute y = 2 in eqn 1</u></em>
2x + 3(2) = 14
2x + 6 = 14
2x = 14 - 6
2x = 8
<h3>x = 4</h3>
Thus the solution to given system of equations are (x, y) = (4, 2)
Answer:
C=47
B=133
Step-by-step explanation:
Answer:
its 50
Step-by-step explanation:
Answer:
At papa's it would be three topping
at little Italy's it would be two topping
I hope this is correct sorry if I'm wrong
Step-by-step explanation:
Answer:
n^6 is the answer
![\frac{1}{\sqrt[4]{n} } * n^{\frac{25}{4} } = \frac{n^{\frac{25}{4} } }{n^{\frac{1}{4} } } = n^{\frac{25}{4} } - n^{\frac{1}{4} } = n^{6}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%5B4%5D%7Bn%7D%20%7D%20%2A%20n%5E%7B%5Cfrac%7B25%7D%7B4%7D%20%7D%20%3D%20%5Cfrac%7Bn%5E%7B%5Cfrac%7B25%7D%7B4%7D%20%7D%20%7D%7Bn%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%20%7D%20%20%3D%20n%5E%7B%5Cfrac%7B25%7D%7B4%7D%20%7D%20-%20n%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%20%3D%20n%5E%7B6%7D)
Step-by-step explanation:
