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maks197457 [2]
3 years ago
10

Write the equation of the line that passes through (1, 3) and has a slope of 2 in point-slope form

Mathematics
2 answers:
aivan3 [116]3 years ago
8 0

Answer:

y-3=2(x-1)

Step-by-step explanation:

Point slope form is y-y1=m(x-x1)

Now we just need to plug in what you have into this equation.

y-3=2(x-1) and this is the point slope form for this line.

raketka [301]3 years ago
3 0

Answer:

y-3= 2(x-1)

Step-by-step explanation:

1. The equation of a line in point slope form is y-y1= m(x-x1)

2. m=slope and (x1,y1) is the point the line passes through

3. The point the line passes through is (1,3)

4, The slope is 2

5. Therefore the answer is y-3=2(x-1)

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Please help me solve this problem ASAP
DiKsa [7]

\bold{\huge{\blue{\underline{ Solution }}}}

<h3><u>Given </u><u>:</u><u>-</u></h3>

  • <u>The </u><u>right </u><u>angled </u><u>below </u><u>is </u><u>formed </u><u>by </u><u>3</u><u> </u><u>squares </u><u>A</u><u>, </u><u> </u><u>B </u><u>and </u><u>C</u>
  • <u>The </u><u>area </u><u>of </u><u>square </u><u>B</u><u> </u><u>has </u><u>an </u><u>area </u><u>of </u><u>1</u><u>4</u><u>4</u><u> </u><u>inches </u><u>²</u>
  • <u>The </u><u>area </u><u>of </u><u>square </u><u>C </u><u>has </u><u>an </u><u>of </u><u>1</u><u>6</u><u>9</u><u> </u><u>inches </u><u>²</u>

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>area </u><u>of </u><u>square </u><u>A</u><u>? </u>

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u><u> </u></h3>

The right angled triangle is formed by 3 squares

<u>We </u><u>have</u><u>, </u>

  • Area of square B is 144 inches²
  • Area of square C is 169 inches²

<u>We </u><u>know </u><u>that</u><u>, </u>

\bold{ Area \: of \: square =  Side × Side }

Let the side of square B be x

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ 144 =  x × x }

\sf{ 144 =  x² }

\sf{ x = √144}

\bold{\red{ x = 12\: inches }}

Thus, The dimension of square B is 12 inches

<h3><u>Now, </u></h3>

Area of square C = 169 inches

Let the side of square C be y

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ 169 =  y × y }

\sf{ 169 =  y² }

\sf{ y = √169}

\bold{\green{ y = 13\: inches }}

Thus, The dimension of square C is 13 inches.

<h3><u>Now, </u></h3>

It is mentioned in the question that, the right angled triangle is formed by 3 squares

The dimensions of square be is x and y

Let the dimensions of square A be z

<h3><u>Therefore</u><u>, </u><u>By </u><u>using </u><u>Pythagoras </u><u>theorem</u><u>, </u></h3>

  • <u>The </u><u>sum </u><u>of </u><u>squares </u><u>of </u><u>base </u><u>and </u><u>perpendicular </u><u>height </u><u>equal </u><u>to </u><u>the </u><u>square </u><u>of </u><u>hypotenuse </u>

<u>That </u><u>is</u><u>, </u>

\bold{\pink{ (Perpendicular)² + (Base)² = (Hypotenuse)² }}

<u>Here</u><u>, </u>

  • Base = x = 12 inches
  • Perpendicular = z
  • Hypotenuse = y = 13 inches

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ (z)² + (x)² = (y)² }

\sf{ (z)² + (12)² = (169)² }

\sf{ (z)² + 144 = 169}

\sf{ (z)² = 169 - 144 }

\sf{ (z)² = 25}

\bold{\blue{ z = 5 }}

Thus, The dimensions of square A is 5 inches

<h3><u>Therefore</u><u>,</u></h3>

Area of square

\sf{ = Side × Side }

\sf{ = 5 × 5  }

\bold{\orange{ = 25\: inches }}

Hence, The area of square A is 25 inches.

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kompoz [17]

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sashaice [31]

Answer:

The answer is: B

Step-by-step explanation:

Hope this helps!

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50 POINTS + BRAINLIEST
Vedmedyk [2.9K]
X + 2y = 6
2y = -x + 6
  y = -1/2 x + 3 so slope = -1/2

parallel lines  has same slope = -1/2
perpendicular lines slope is opposite and reciprocal so slope = 2  
if slope not equal either -1/2 or 2 then neither.

y = -1/2 x - 5 ....m= - 1/2....  parallel

-2x + y = -4
          y = 2x - 4...m = 2 ....perpendicular

-x + 2y = 2
2y = x + 2
y = 1/2 x + 1 ...m = 1/2 ...neither

x + 2y = -2
2y = -x - 2
 y = -1/2 x - 1 ...m = -1/2 .....parallel

hope it helps
3 0
3 years ago
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